django - Django表单逻辑的更好模式吗？

Question

因此，Django表单的 View 逻辑的标准模式为:

def contact(request):
    if request.method == 'POST': # If the form has been submitted...
        form = ContactForm(request.POST) # A form bound to the POST data
        if form.is_valid(): # All validation rules pass
            # Process the data in form.cleaned_data
            # ...
            return HttpResponseRedirect('/thanks/') # Redirect after POST
    else:
        form = ContactForm() # An unbound form

    return render_to_response('contact.html', {
        'form': form,
    })

在简单的情况下这很好，但是如果您的应用程序逻辑变得更加复杂，则很容易陷入大量嵌套的IF语句中。

任何人都可以分享他们自己的更干净的方法来避免嵌套IF和依赖于失败情况的逻辑吗？

我对不依赖于其他第三方应用程序的答案特别感兴趣。

Answer 1

包含的基于类的 View 之一是FormView(documentation)。您需要关注的两个主要方法是form_valid和form_invalid。

from django.views.generic import FormView

from myapp.forms import MyForm

class MyView(FormView):

    template_name = 'edit_something.html'
    form_class = MyForm
    success_url = '/success/' # you should use `reverse`, but let's stay focused.

    def form_valid(self, form):
        """
        This is what's called when the form is valid.
        """

        return super(MyView, self).form_valid(form)

    def form_invalid(self, form):
        """
        This is what's called when the form is invalid.
        """

        return self.render_to_response(self.get_context_data(form=form))

另外，您可以覆盖post，get或put方法，并根据每种请求类型处理表单。