unix - 使用 awk 命令从文件中提取第一行

Question

我一直在上网UNIX当然，并遇到了我一直坚持的这个问题。将不胜感激任何帮助!

You are provided with a set of files each one of which contains personal details about an individual. Each file is laid out in the following format, with one file per individual:

name:Niko Tanaka 
age:41 
occupation:Doctor

我知道答案必须采用以下形式:

n=$(awk -F: '   /   /{print }'  filename)

Answer 1

n=$(awk -F: '/name/{print $2}' infile)

/ / 里面的任何内容是正则表达式。在这种情况下，您只想匹配包含“名称”的行。