我正在使用 Classic Asp 来构建对一个 url 的请求,现在这个问题是成功的
是我想从函数返回请求对象并获得以下内容
问题:
对象不支持此属性或方法,
我该怎么做 ?
Set objSrvHTTP = Server.CreateObject ("Msxml2.ServerXMLHTTP.3.0")
objSrvHTTP.open "POST","Https://",False,"",""
objSrvHTTP.SetRequestHeader "Content-Type", "text/xml"
objSrvHTTP.SetRequestHeader "Authorization", "Basic " & EncodeBase64("sales@nutritionexpress.co.uk:f00tball")
objSrvHTTP.SetRequestHeader "dev-t", " MyAccessKey "
objSrvHTTP.SetRequestHeader "Cookie", "ubid-main=172-9288630-2514702; session-id=026-6553457-3334020; session-id-time=1191279600l;"
objSrvHTTP.send
BuildRequest=objSrvHTTP
谢谢
最佳答案
改变
BuildRequest=objSrvHTTP
到
Set BuildRequest=objSrvHTTP
返回对象。
关于asp-classic - 从经典 Asp 返回对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3907007/