新 String ("a") 对象的 JavaScript(严格)相等

Question

有在ECMAScript Language Specification 11.9.1 等于运算符 (==):

NOTE 3 The equality operator is not always transitive. For example, there might be two distinct String objects, each representing the same String value; each String object would be considered equal to the String value by the == operator, but the two String objects would not be equal to each other. For Example:

• new String("a") == "a" and "a" == new String("a") are both true.
• new String("a") == new String("a") is false.

但在11.9.6 严格相等比较算法中:

7. Return true if x and y refer to the same object. Otherwise, return false.

但是没有，用jsc

new String("a")===new String("a")

是真的。

那是 jsc.exe 错误吗？或者它们是同一个对象？为什么？

Answer 1

js中的运算符===如果类型相等且值相等则返回true。所以它返回 true 是正确的，因为它们都是 String 对象并且它们的值是“a”。

查看文档 http://www.w3schools.com/js/js_comparisons.asp