我希望我的 Web 应用程序能够登录 AWS。我正在使用 Eclipse JEE。关于框说:
Eclipse IDE for Enterprise Java Developers.
Version: 2019-03 (4.11.0)
Build id: 20190314-1200
我有以下代码:
index.html:
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-type" content="text/html; charset=utf-8">
<title>Hello AWS Web World!</title>
<link rel="stylesheet" href="styles/styles.css" type="text/css"
media="screen">
</head>
<body>
<h1>Post</h1>
<div>
<form action="LoginServlet" method="post">
Name:<input type="text" name="name"><br>
Password:<input type="password" name="password"><br>
<input type="submit" value="submit">
</form>
</div>
<h1>Get</h1>
<div>
<form action="LoginServlet" method="get">
Name:<input type="text" name="name"><br>
Password:<input type="password" name="password"><br>
<input type="submit" value="submit">
</form>
</div>
</body>
</html>
索引.jsp
<%@ page language="java" contentType="text/html; charset=utf-8" pageEncoding="utf-8" %>
<%@ page import="com.amazonaws.*" %>
<%@ page import="com.amazonaws.auth.*" %>
<%@ page import="com.amazonaws.auth.profile.*" %>
<%@ page import="com.amazonaws.services.ec2.*" %>
<%@ page import="com.amazonaws.services.ec2.model.*" %>
<%@ page import="com.amazonaws.services.s3.*" %>
<%@ page import="com.amazonaws.services.s3.model.*" %>
<%@ page import="com.amazonaws.services.dynamodbv2.*" %>
<%@ page import="com.amazonaws.services.dynamodbv2.model.*" %>
<%! // Share the client objects across threads to
// avoid creating new clients for each web request
private AmazonEC2 ec2;
private AmazonS3 s3;
private AmazonDynamoDB dynamo;
%>
<%
/*
* AWS Elastic Beanstalk checks your application's health by periodically
* sending an HTTP HEAD request to a resource in your application. By
* default, this is the root or default resource in your application,
* but can be configured for each environment.
*
* Here, we report success as long as the app server is up, but skip
* generating the whole page since this is a HEAD request only. You
* can employ more sophisticated health checks in your application.
*/
if (request.getMethod().equals("HEAD")) return;
%>
<%
if (ec2 == null) {
AWSCredentialsProviderChain credentialsProvider = new AWSCredentialsProviderChain(
new InstanceProfileCredentialsProvider(),
new ProfileCredentialsProvider("default"));
ec2 = new AmazonEC2Client(credentialsProvider);
s3 = new AmazonS3Client(credentialsProvider);
dynamo = new AmazonDynamoDBClient(credentialsProvider);
}
%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-type" content="text/html; charset=utf-8">
<title>Hello AWS Web World!</title>
<link rel="stylesheet" href="styles/styles.css" type="text/css" media="screen">
</head>
<body>
<div id="content" class="container">
<div class="section grid grid5 s3">
<h2>Amazon S3 Buckets:</h2>
<ul>
<% for (Bucket bucket : s3.listBuckets()) { %>
<li> <%= bucket.getName() %> </li>
<% } %>
</ul>
</div>
<div class="section grid grid5 sdb">
<h2>Amazon DynamoDB Tables:</h2>
<ul>
<% for (String tableName : dynamo.listTables().getTableNames()) { %>
<li> <%= tableName %></li>
<% } %>
</ul>
</div>
<div class="section grid grid5 gridlast ec2">
<h2>Amazon EC2 Instances:</h2>
<ul>
<% for (Reservation reservation : ec2.describeInstances().getReservations()) { %>
<% for (Instance instance : reservation.getInstances()) { %>
<li> <%= instance.getInstanceId() %></li>
<% } %>
<% } %>
</ul>
</div>
</div>
</body>
</html>
登录Servlet.java
package package10_2;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
@WebServlet(name="LoginServlet", urlPatterns= {"/"})
public class LoginServlet extends HttpServlet {
/**
*
*/
private static final long serialVersionUID = 1L;
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
System.out.println("doPost");
response.setContentType("text/html");
PrintWriter out=response.getWriter();
out.println("doPost");
Boolean authenticated = request.authenticate(response);
System.out.println("authenticated=" + authenticated);
out.println("authenticated=" + authenticated);
String authType = request.getAuthType();
System.out.println("auth type =" + authType);
out.println("auth type =" + authType);
String remoteUser = request.getRemoteUser();
System.out.println("remote user =" + remoteUser);
out.println("remote user =" + remoteUser);
out.close();
}
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
System.out.println("doGet");
response.setContentType("text/html");
PrintWriter out=response.getWriter();
out.println("doGet");
String authType = request.getAuthType();
System.out.println("auth type =" + authType);
out.println("auth type =" + authType);
String remoteUser = request.getRemoteUser();
System.out.println("remote user =" + remoteUser);
out.println("remote user =" + remoteUser);
out.close();
}
}
当我使用第一个使用 post 方法的表单时，我输入了正确的用户名和密码，但是当我点击提交时，我得到一个登录对话框，要求输入用户名和密码。在这种情况下，用户名是 tina。以下是之后网站上显示的内容:
doPost authenticated=true auth type =BASIC remote user =tina
当我使用第二种使用 get 方法的表单时，我输入了正确的用户名和密码，但是当我点击提交时，网站显示:
doGet auth type =null remote user =null
我应该使用post方式还是get方式登录？我想我应该使用 get 方法。
如何让 post 方法处理用户在 index.html 页面的表单中输入的用户名和密码值？
最佳答案
Http GET 不支持表单提交，必须使用JS 将它们添加到查询参数上。 但它存在安全风险。
所以通常 GET 不是处理登录的好方法。
关于amazon-web-services - 如何使用 Eclipse JEE 从我的 Web 应用程序登录 AWS？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/60119700/