我有一个 xml URL 文件,其中有空格我想用 %20 替换空格.. 怎么做????
SAXParserFactory spf = SAXParserFactory.newInstance();
SAXParser sp = spf.newSAXParser();
XMLReader xr = sp.getXMLReader();
/** Send URL to parse XML Tags */
URL sourceUrl = new URL(
"http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES");
XMLHandlerartistspace myXMLHandler = new XMLHandlerartistspace();
xr.setContentHandler(myXMLHandler);
xr.parse(new InputSource(sourceUrl.openStream()));
最佳答案
试试这个:
String temp = http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES
temp = temp.replaceAll(" ", "%20");
URL sourceUrl = new URL(temp);
关于java - 如何在android中插入%20代替空格,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6045377/