我想要从纪元(1970-01-01)开始的天数。我试过 joda-time
try {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date1 = sdf.parse("2013-05-03 07:00:00");
Date date2 = sdf.parse("2013-05-03 23:30:00");
MutableDateTime epoch = new MutableDateTime();
epoch.setDate(0); //Set to Epoch time
System.out.println("Epoch: " + epoch);
Days days1 = Days.daysBetween(epoch, new MutableDateTime(date1.getTime()));
Days days2 = Days.daysBetween(epoch, new MutableDateTime(date2.getTime()));
System.out.println("1) Days Since Epoch: " + days1.getDays());
System.out.println("2) Days Since Epoch: " + days2.getDays());
} catch (ParseException e) {
e.printStackTrace();
}
并使用逻辑:
// Create Calendar instance
Calendar calendar1 = Calendar.getInstance();
Calendar calendar2 = Calendar.getInstance();
calendar2.setTime(date);
// Set the values for the calendar fields YEAR, MONTH, and DAY_OF_MONTH.
//calendar1.set(calendar1.YEAR, calendar1.MONTH, Calendar.DAY_OF_MONTH);
calendar1.set(1970, 1, 1);
/*
* Use getTimeInMillis() method to get the Calendar's time value in
* milliseconds. This method returns the current time as UTC
* milliseconds from the epoch
*/
long miliSecondForDate1 = calendar1.getTimeInMillis();
long miliSecondForDate2 = calendar2.getTimeInMillis();
// Calculate the difference in millisecond between two dates
long diffInMilis = miliSecondForDate2 - miliSecondForDate1;
/*
* Now we have difference between two date in form of millsecond we can
* easily convert it Minute / Hour / Days by dividing the difference
* with appropriate value. 1 Second : 1000 milisecond 1 Hour : 60 * 1000
* millisecond 1 Day : 24 * 60 * 1000 milisecond
*/
long diffInSecond = diffInMilis / 1000;
long diffInMinute = diffInMilis / (60 * 1000);
long diffInHour = diffInMilis / (60 * 60 * 1000);
long diffInDays = diffInMilis / (24 * 60 * 60 * 1000);
if(logger.isInfoEnabled()) {
logger.info("Difference in Seconds : " + diffInSecond);
logger.info("Difference in Minute : " + diffInMinute);
logger.info("Difference in Hours : " + diffInHour);
logger.info("Difference in Days : " + diffInDays);
}
我得到了这两个的差异结果。有人可以在我错的地方提供帮助。
谢谢。
最佳答案
17006 和 17007 相差一天。这种差异很可能来自您所在时区的 7:00 和 23:30 在其他时区的不同日期,例如 UTC。或者反过来说,UTC 中的那些时间恰好在您所在时区的不同日期。因此计数减一。我不知道 JodaTime,所以我不能给你确切的细节。
16975 和 17006 之间的差异是 31 天或一整月。我可以准确地告诉你这是从哪里来的。 Calendar
月份是从 0 开始的:一月是 0 月,二月是 1 月,等等。所以 calendar1.set(1970, 1, 1)
将您的日历设置为 1970 年 2 月 1 日,即纪元后 31 天。使用calendar1.set(1970, Calendar.JANUARY, 1)
反而。您还需要控制 Calendar
的小时、分钟和秒。 .您可以调用clear()
之前 set()
以确保时间是在午夜。
如果你可以使用 Java 8,你可以这样做:
DateTimeFormatter format = DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss");
OffsetDateTime t1 = LocalDateTime.parse("2013-05-03 07:00:00", format)
.atOffset(ZoneOffset.UTC);
OffsetDateTime t2 = LocalDateTime.parse("2013-05-03 23:30:00", format)
.atOffset(ZoneOffset.UTC);
System.out.println("1) Days Since Epoch: " + ChronoUnit.DAYS.between(Instant.EPOCH, t1));
System.out.println("2) Days Since Epoch: " + ChronoUnit.DAYS.between(Instant.EPOCH, t2));
这打印:
1) Days Since Epoch: 15828
2) Days Since Epoch: 15828
如果您想使用不同的时区:
DateTimeFormatter format = DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss");
ZonedDateTime t1 = LocalDateTime.parse("2013-05-03 07:00:00", format)
.atZone(ZoneId.systemDefault());
ZonedDateTime t2 = LocalDateTime.parse("2013-05-03 23:30:00", format)
.atZone(ZoneId.systemDefault());
System.out.println("1) Days Since Epoch: " + ChronoUnit.DAYS.between(Instant.EPOCH, t1));
System.out.println("2) Days Since Epoch: " + ChronoUnit.DAYS.between(Instant.EPOCH, t2));
您可以填写所需的时区而不是
ZoneId.systemDefault()
.
关于java - 从纪元开始获取天数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43065608/