我正在参加一个测试类,主要是为了自学。下面是类:
class Connection
{
public $con;
public $dbSelected;
public $activeConnection;
public $dataBaseName;
function __contruct($dbUserName, $dbPassword, $server = "localhost")
{
$this->con = mysql_connect($server,$dbUserName,$dbPassword);
if(!$this->$con)
{
$this->activeConnection = false;
}
else
{
$this->activeConnection = true;
}
}
public function dbConnect($dbName, $identifyer = null)
{
if ($identifyer === null)
{
$identifyer = $this->con;
}
$this->dbSelected = mysql_select_db($dbName, $identifyer);
$this->dataBaseName = $dbName;
if($this->dbSelected != true)
{
$this->connectionErrorReport(__LINE__);
}
}
public function cleanData( array $submission)
{
unset($submission["throughTheCleaners"]);
foreach($submission as $key => $value)
{
if(is_array($value))
{
$data[$key] = $this->cleanData($value);
}
else
{
$data[$key] = mysql_real_escape_string($value);
}
}
$data["throughTheCleaners"] = true;
return $data;
}
public function query($query, $dataSent)
{
if($dataSent["throughTheCleaners"] != true)
{
die("you must clean the data".__LINE__);
}
if($this->activeConnection == true && $this->dbSelected == true)
{
$result = mysql_query($query) or queryErrorReport($query, __LINE__);
$i = 0;
while($row = mysql_fetch_array($result))
{
foreach($row as $key => $value)
{
$data[$i][$key] = $value;
$i++;
}
}
return $data;
}
else
{
$this->$connectionErrorReport(__LINE__);
}
}
public function connectionErrorReport($line = __LINE__)
{
$error = "There has been a connection error on line ".$line."</br>";
if($this->activeConnection == false)
{
$error.= "Active Connection Error <br/>";
}
if($this->dbSelected == false)
{
$error.= "Data Base Selection Error <br/>";
}
die($error.mysql_error());
}
public function queryErrorReport($query, $line = __LINE__)
{
die("There was a query error on ".$line."<br />$query<br/>".mysql_error());
}
function __destruct() {
mysql_close($this->con);
}
}
我终其一生都想不通为什么它不会在构造函数调用期间获取存储在 $con
变量中的 mysql 数据库资源并在其他函数中使用它。
最终在另一个类中会有一个字符串加密函数,但我目前遇到的唯一错误是连接类。
因此抛出错误的页面如下所示:
include 'connection.php';
include 'loginClass.php';
$longinConnection = new Connection('***USERNAMEHERE***','***PASSWORD***');
$longinConnection->dbConnect("***DBTOCONNECTTO***");
echo Authoriz::encryptPassword("***USERPASSWORD***",$longinConnection);
此页面测试了 encryptPassword
函数,但我什至无法让 Connection
类工作。它抛出的错误如下:
Warning: mysql_select_db() expects parameter 2 to be resource, null given in [PATH] on line 27 There has been a connection error on line 31 Active Connection Error Data Base Selection Error
Warning: mysql_close() expects parameter 1 to be resource, null given in [PATH] on line 103
在我看来,由于某种原因没有设置 $con
变量,如果能深入了解我做错了什么,我们将不胜感激。
最佳答案
你拼错了 __construct
所以当你初始化类时它没有触发,也没有初始化 $this->con
关于php - OOP PHP First Class Mysql数据库连接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9692965/