标签 sql sql-server
<分区>
如果我下面有这张表
id time
start 08.00 AM
stop 09.00 AM
stop 09.30 AM
start 09.30 AM
start 11.00 AM
start 11.30 AM
stop 11.40 AM
stop 12.00 PM
我想要的输出只包含每个第一次开始和每次停止后开始和最近停止
有什么解决办法吗？
这就是我想要的输出方式:
id time
start 08.00 AM
stop 09.00 AM
start 09.30 AM
stop 11.40 AM
stop 12.00 PM
最佳答案
没有任何主键或每行有一些不同的 id ......我想到的唯一解决方案是这样的:
select rn, id , time
from
(select ROW_NUMBER() over (order by time) as rn, id, time from test
where id = 'start'
union
select ROW_NUMBER() over (order by time) as rn, id, time from test
where id = 'stop'
) d
order by rn
基本上我在开始行和停止行之间做了一个联合，如下所示:
(select ROW_NUMBER() over (order by time) as rn, id, time from test
where id = 'start'
union
select ROW_NUMBER() over (order by time) as rn, id, time from test
where id = 'stop'
) d
返回:
1 start 08.00
2 start 11.00
3 start 12.00
4 start 13.00
1 stop 09.00
2 stop 10.00
3 stop 14.00
4 stop 15.00
来自原始输入:
id time
start 08.00
stop 09.00
stop 10.00
start 11.00
start 12.00
start 13.00
stop 14.00
stop 15.00
现在你只需要按它们自己的行号来排序......就是那个 rn。
最后你会得到:
1 start 08.00
1 stop 09.00
2 start 11.00
2 stop 10.00
3 start 12.00
3 stop 14.00
4 start 13.00
4 stop 15.00
@注意:我的示例值与您的值接近...但是是虚构的...
关于SQL Server 选择行，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14577406/