如何从内联模型管理员访问父实例?
我的目标是根据父实例的状态覆盖has_add_permission
函数。如果父级的状态不同于1,则我不允许添加子级。
class ChildInline(admin.TabularInline):
model = Child
form = ChildForm
fields = (
...
)
extra = 0
def has_add_permission(self, request):
# Return True only if the parent has status == 1
# How to get to the parent instance?
#return True
class ParentAdmin(admin.ModelAdmin):
inlines = [ChildInline,]
最佳答案
Django <2.0答案:
使用Django的Request对象(您可以访问)检索request.path_info
,然后从resolve
匹配项中的参数中检索PK。例:
from django.contrib import admin
from django.core.urlresolvers import resolve
from app.models import YourParentModel, YourInlineModel
class YourInlineModelInline(admin.StackedInline):
model = YourInlineModel
def get_parent_object_from_request(self, request):
"""
Returns the parent object from the request or None.
Note that this only works for Inlines, because the `parent_model`
is not available in the regular admin.ModelAdmin as an attribute.
"""
resolved = resolve(request.path_info)
if resolved.args:
return self.parent_model.objects.get(pk=resolved.args[0])
return None
def has_add_permission(self, request):
parent = self.get_parent_object_from_request(request)
# Validate that the parent status is active (1)
if parent:
return parent.status == 1
# No parent - return original has_add_permission() check
return super(YourInlineModelInline, self).has_add_permission(request)
@admin.register(YourParentModel)
class YourParentModelAdmin(admin.ModelAdmin):
inlines = [YourInlineModelInline]
Django> = 2.0答案:
归功于Mark Chackerian进行以下更新:
使用Django的Request对象(您可以访问)检索
request.path_info
,然后从resolve
匹配项中的参数中检索PK。例:from django.contrib import admin
from django.urls import resolve
from app.models import YourParentModel, YourInlineModel
class YourInlineModelInline(admin.StackedInline):
model = YourInlineModel
def get_parent_object_from_request(self, request):
"""
Returns the parent object from the request or None.
Note that this only works for Inlines, because the `parent_model`
is not available in the regular admin.ModelAdmin as an attribute.
"""
resolved = resolve(request.path_info)
if resolved.args:
return self.parent_model.objects.get(pk=resolved.args[0])
return None
def has_add_permission(self, request):
parent = self.get_parent_object_from_request(request)
# Validate that the parent status is active (1)
if parent:
return parent.status == 1
# No parent - return original has_add_permission() check
return super(YourInlineModelInline, self).has_add_permission(request)
@admin.register(YourParentModel)
class YourParentModelAdmin(admin.ModelAdmin):
inlines = [YourInlineModelInline]
关于django - Django:从内联模型管理员访问父实例,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32150088/