java - 如何将 JSONObject 从 Android 应用程序传递到 PHP 文件？

Question

我想向 PHP 服务器发送一个简单的 JSON 对象，但是当我尝试在服务器端检索该对象时，没有任何内容，我的意思是我的 $_POST 变量为空。服务器端是 PHP 5.2，我正在使用 android 模拟器 10 ...有人可以看看我的代码并告诉我出了什么问题吗？ 非常感谢

public void uploadJSon() throws ClientProtocolException, IOException, JSONException{
       HttpClient httpclient = new DefaultHttpClient();
       String url = "http://so-dev-deb.niv2.com/suivi_activite/test.php";
       HttpPost httppost = new HttpPost(url);
       JSONObject json = new JSONObject();

       json.put("username", "bob");
       json.put("email", "test@testsite.com");
       List <NameValuePair> nvps = new ArrayList <NameValuePair>();

       nvps.add(new BasicNameValuePair("value", json.toString()));
       httppost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));                 

       URL test_url = new URL(url);
       URLConnection connection = test_url.openConnection();
       connection.setDoOutput(true);

       HttpResponse response;
       response = httpclient.execute(httppost);
       Log.i("NVPS",nvps.get(0).toString());
       Log.i("JSON",json.toString());
       Log.i("response", response.getEntity().getContent().toString());
       Log.i("response status",response.getStatusLine().toString());

       BufferedReader in = new BufferedReader(
             new InputStreamReader(
             connection.getInputStream()));

       String decodedString;

       while ((decodedString = in.readLine()) != null) {
          //System.out.println(decodedString);
          Log.i("info 10",decodedString);
       }
       in.close();

    }

服务器端 test.php 是:

<?php 
    $tmp = json_decode($_POST['value']); 
    var_dump($tmp); 
?>

Answer 1

我通常采用这种方法在 Java 代码中生成 JSON 对象:

StringWriter writer = new StringWriter();
JSONWriter jsonWriter = new JSONWriter(writer);
jsonWriter.object();
jsonWriter.key("key1").value("test1");
jsonWriter.key("key2").value("test2");
jsonWriter.endObject();
String toSend = writer.toString();