我正在尝试匹配: “{{ loop (something) }}”和第一个 {{/loop (that something) }}
之间的所有内容文本示例:
{{ LOOP data }}
<span> Member key = {{.key}} </span>
<span> Member value = {{.}} </span>
<span> Member member = {{name}} </span>
<span> Iteration number = {{.counter}} </span>
{{ /LOOP data }}
这是正则表达式不起作用:
/\{\{\s+loop\s+(.+?)\s+\}\}([\w\W]+?)\{\{\s+\/loop\s$1\s+\}\}/i
如您所见,我正在尝试重用第一个匹配组和“$1”:我错过了什么?
PHP代码如下:
$text = '
{{ LOOP data }}
<span> Member key = {{.key}} </span>
<span> Member value = {{.}} </span>
<span> Member member = {{name}} </span>
<span> Iteration number = {{.counter}} </span>
{{ /LOOP data }}
';
preg_match('/\{\{\s+loop\s+(.+?)\s+\}\}([\w\W]+?)\{\{\s+\/loop\s\1\s+\}\}/i', $text, $match);
print_r($match);
die;
最佳答案
我相信你想要 \1
,而不是 $1
。
更多信息:http://www.regular-expressions.info/brackets.html#usebackrefinregex
关于php - 在正则表达式中重用匹配组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14318955/