java - PHP 中等效的 AES 128 位

Question

我有这段 Java 代码，它使用 AES 128 位将源字符串加密为 Base64 加密值。但是我没能找到产生相同结果的类似 PHP 函数。任何帮助将不胜感激

    String key = "1234567890123456";
    String source = "The quick brown fox jumped over the lazy dog";

    byte[] raw = key.getBytes();
    SecretKeySpec skeySpec = new SecretKeySpec(raw, "AES");

    // Instantiate the cipher
    Cipher cipher = Cipher.getInstance("AES");

    cipher.init(Cipher.ENCRYPT_MODE, skeySpec);

    byte[] encrypted = cipher.doFinal(source.getBytes());
    System.out.println(new String(Base64.encodeBase64(encrypted)));

Answer 1

这就是答案。感谢@owlstead 和他提到的线程中原始答案的所有者

<?php
function encrypt($str, $key){
     $block = mcrypt_get_block_size('rijndael_128', 'ecb');
     $pad = $block - (strlen($str) % $block);
     $str .= str_repeat(chr($pad), $pad);
     return base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_128, $key, $str, MCRYPT_MODE_ECB));
}

function decrypt($str, $key){ 
     $str = base64_decode($str);
     $str = mcrypt_decrypt(MCRYPT_RIJNDAEL_128, $key, $str, MCRYPT_MODE_ECB);
     $block = mcrypt_get_block_size('rijndael_128', 'ecb');
     $pad = ord($str[($len = strlen($str)) - 1]);
     $len = strlen($str);
     $pad = ord($str[$len-1]);
     return substr($str, 0, strlen($str) - $pad);
}
?>