sql - 使用 Like 选择的 ActionScript 和 SQLite 参数

Question

我尝试在谷歌上查找，但没有运气......

我有一个 SELECT SQLStatement 并且我想使用 LIKE 运算符，但参数不起作用并且查询给我一个错误

    public function getUsersList(username:String):SQLStatement
    {           
        selectRecord= new SQLStatement();
        selectRecord.sqlConnection = connection;                                
        selectRecord.text =
            "SELECT id_user, username,password,profile,leg_cliente " +
            "FROM userlist  " +
            "WHERE username like '%:username%'";            
        selectRecord.parameters[":username"] = username;

        return selectRecord;
    }

我得到的错误是

':username' parameter name(s) found in parameters property but not in the SQL specified.

Answer 1

我解决了将通配符 % 放在参数而不是语句中的问题...

        selectRecord.text =
            "SELECT id_user, username,password,profile,leg_cliente " +
            "FROM userlist  " +
            "WHERE username like :username";            
        selectRecord.parameters[":username"] = "%"+ username+"%";

触发启动问题是因为查询类似于

    selectRecord.text =
        "SELECT id_user, username,password,profile,leg_cliente " +
        "FROM userlist  " +
        "WHERE username like '%:username%'";    

在语句中放入单引号不会让语句设置参数，我想是因为参数键(在statement.text中)被视为文本而不是参数本身......