我有以下两个表:
表作者:
AuthorID Name
A John
B Alex
C Carl
表作者兼容性:
AuthorID1 AuthorID2 Compatibility
A B 5.0
A C 4.0
B C 4.5
我想制作以下内容:
AuthorID1 Name1 AuthorID2 Name2 Compatibility
A John B Alex 5.0
A John C Carl 4.0
B Alex C Carl 4.5
这是我尝试过的方法,但我知道它不起作用:
select AuthorID1, A.Name, AuthorID2, B.Name, Compatibility
from AuthorsCompatibility, Authors as A, Authors as B
where AuthorID1=A.AuthorID and AuthorID2=B.AuthorID
最佳答案
SELECT ac.AuthorID1, a.Name, ac.AuthorID2, b.Name, ac.Compatibility
FROM AuthorsCompatibility ac
INNER JOIN AUTHORS a ON ac.AuthorID1 = a.AuthorID
INNER JOIN AUTHORS b ON ac.AuthorID2 = b.AuthorID
关于sql - 查询没有产生它应该产生的结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39097783/