我知道这个问题可能已经得到解答,但我遇到的许多示例都涉及使用 INNER JOIN 将数据从一个表传输到另一个表,而我的情况有点不同。
基本上我想做的就是将此 SELECT 语句转换为 Update 语句。
SELECT
SR, 100. * Cast(Round(AVG(Three_1 + Three_2 + Three_3 + Three_4 + Three_5 + Three_6 + Three_7 + Five_1 + Six_1 + Six_3) / 38,0) as int)
FROM
MainDB
WHERE
Ctype = 'Call'
GROUP BY
SR
我能够成功计算一些列的百分比,然后我想用该信息更新列。我的第一次尝试是这样的
UPDATE QAMainDB
SET TCX_score = 100. * avg(three_1 + Three_2 + Three_3 + Three_4 + Three_5 + Three_6 + Three_7 + Five_1 + Six_1 + Six_3) / 38
我收到错误:
An aggregate may not appear in the set list of an UPDATE statement.
在做了更多的尝试和错误之后,我尝试了这种方法来声明堆栈上前面示例中的变量。
Declare @Result Decimal = 0
SET @Result = 100. * Cast(round(avg(three_1 + Three_2 + Three_3 + Three_4 + Three_5 + Three_6 + Three_7 + Five_1 + Six_1 + Six_3) / 38,0) as int)
UPDATE QAMainDB
SET TCX_score = @Result
WHERE Ctype = 'Call'
但是失败了,我想知道你们中是否有人可以帮助我,引导我走向正确的方向。我对 SQL 还很陌生,所以请耐心等待。
感谢您的宝贵时间。
最佳答案
您如何匹配列?我猜测 SR
是用于表之间匹配的列:
WITH m as (
SELECT SR, 100. * Cast(Round(AVG(Three_1 + Three_2 + Three_3 + Three_4 + Three_5 + Three_6 + Three_7 + Five_1 + Six_1 + Six_3) / 38,0) as int) as val
FROM MainDB
WHERE Ctype = 'Call'
GROUP BY SR
)
Update QAMainDB
SET TCX_score = val
FROM QAMainDB JOIN
m
ON m.SR = QAMainDB.SR;
关于sql-server - 使用 SQL Server 中的一张表上的聚合函数更新查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40145038/