我有一个学生成绩表,其架构如下:
Student
--------
SNO
Marks
我想产生这样的结果:
MarksRange Count
---------- ------
0 10
10 2
20 43
: :
100 2
以上结果表明有:
- 10 名得零分的学生,
- 2 名学生如何获得 1 到 10 之间的分数,
- 43 从 11-20
- 等等。
谁能告诉我如何编写产生此结果的查询?
最佳答案
试试这个:
DECLARE @Student table (SNO int,Marks int)
INSERT INTO @Student VALUES (1, 0)
INSERT INTO @Student VALUES (1, 3)
INSERT INTO @Student VALUES (1, 45)
INSERT INTO @Student VALUES (1, 95)
INSERT INTO @Student VALUES (1, 85)
INSERT INTO @Student VALUES (1, 97)
INSERT INTO @Student VALUES (1, 92)
DECLARE @StartNumber int
,@EndNumber int
SELECT @StartNumber=0
,@EndNumber=100
;WITH AllNumbers AS
(
SELECT @StartNumber AS Number
UNION ALL
SELECT Number+10
FROM AllNumbers
WHERE Number<@EndNumber
)
SELECT
n.number AS MarksRange,COUNT(s.SNO) AS CountOf
FROM AllNumbers n
LEFT OUTER JOIN @Student s ON s.Marks=n.Number OR (s.Marks>n.Number-10 AND s.Marks<=n.Number)
GROUP BY n.number
输出:
MarksRange CountOf
----------- -----------
0 1
10 1
20 0
30 0
40 0
50 1
60 0
70 0
80 0
90 1
100 3
如果您使用的不是 SQL Server 2005+,则需要将 CTE 替换为 Numbers table .并使用如下查询:
SELECT
n.number,COUNT(s.SNO),0 AS CountOf
FROM Numbers n
LEFT OUTER JOIN @Student s ON s.Marks=n.Number OR (s.Marks>n.Number-10 AND s.Marks<=n.Number)
WHERE n.Number>=@StartNumber AND n.Number<=@EndNumber AND CONVERT(decimal(3,1),n.Number/10)=n.Number/10.0
GROUP BY n.number
关于sql-server - 基于范围的列数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3727867/