sql-server - 不能使用 MIN、MAX 等 SQL Server 2012

Question

我有这样的查询:

 select 
      FirstName, LastName, BirthDate,
      GETDATE() AS [Today],
      CAST (DATEDIFF (DD, BirthDate, GETDATE())/365.25 AS INT) AS [Age]
FROM
      Employees
WHERE CAST (DATEDIFF (DD, BirthDate, GETDATE())/365.25 AS INT) >=55
ORDER BY LastName ASC

我想找到最大的、最小的和平均年龄，我以为我可以做到，但显然我做不到。如何使这项工作？

 select 
     FirstName, LastName, BirthDate,
     GETDATE() AS [Today],
     CAST (DATEDIFF (DD, BirthDate, GETDATE())/365.25 AS INT) AS [Age],
     MIN (DATEDIFF (DD, BirthDate, GETDATE())/365.25 AS INT)
FROM
     Employees
WHERE 
     CAST (DATEDIFF (DD, BirthDate, GETDATE())/365.25 AS INT) >=55
ORDER BY 
     LastName ASC

错误:

Msg 195, Level 15, State 10, Line 5
'MIN' is not a recognized built-in function name.

Answer 1

这是我找到的解决方案。感谢大家的帮助!

SELECT
       MAX (CAST (DATEDIFF (DD, BirthDate, GETDATE())/365.25 AS INT)) AS [The Biggest Age]
     , MIN (CAST (DATEDIFF (DD, BirthDate, GETDATE())/365.25 AS INT)) AS [The Smallest Age]
     , AVG (CAST (DATEDIFF (DD, BirthDate, GETDATE())/365.25 AS INT)) AS [The Average Age]
FROM
      Employees