我在以下程序中使用了一个处理程序，我想在 i=5 时停止它，但处理程序不会停止并连续运行。
b1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
handler = new Handler();
runnable = new Runnable() {
public void run() {
try {
Toast.makeText(getApplicationContext(), "Handler is working", Toast.LENGTH_LONG).show();
System.out.print("Handler is working");
if(i==5){
//Thread.currentThread().interrupt();
handler.removeCallbacks(runnable);
System.out.print("ok");
Toast.makeText(getApplicationContext(), "ok", Toast.LENGTH_LONG).show();
}
i++;
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
handler.postDelayed(this, 5000);
}
};
handler.postDelayed(runnable, 5000);
//return;
}
});
最佳答案
因为您在删除回调后再次调用 postDelayed()。请使用此代码:
final Handler handler = new Handler();
final Runnable runnable = new Runnable() {
public void run() {
Log.d("Runnable","Handler is working");
if(i == 5){ // just remove call backs
handler.removeCallbacks(this);
Log.d("Runnable","ok");
} else { // post again
i++;
handler.postDelayed(this, 5000);
}
}
};
//now somewhere in a method
b1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
handler.removeCallbacks(runnable);
handler.postDelayed(runnable, 5000);
}
});
关于java - 如何停止 Handler Runnable？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18671067/