我希望 json\\"something"
始终返回相同类型的对象(或者至少是始终同构的对象)对于具有相同模式的数据的相同查询 但是,请考虑:
val json1 = ("people" -> List(
("person" -> ("name" -> "Joe")),
("person" -> ("name" -> "Marilyn"))))
val json2 = ("people" -> List(
("person" -> ("name" -> "Joe"))))
val json3 = ("people" -> List[(String, String)]())
println((json1 \\ "name")) // JObject(List(JField(name,JString(Joe)), JField(name,JString(Marilyn))))
println((json2 \\ "name")) // JString(Joe)
println((json3 \\ "name")) // JObject(List())
// which causes the following construction to sometimes fail
println((json1 \\ "name").children map { case JField(_, JString(name)) => name })
// List(Joe, Marilyn)
println((json2 \\ "name").children map { case JField(_, JString(name)) => name })
// List() !!!!!
println((json3 \\ "name").children map { case JField(_, JString(name)) => name })
// List()
...因此 n = 0 和 n >= 2 的情况得到一致处理,但 n = 1 的特殊情况为 JValue
。
为什么会这样?是设计使然吗?
与 List
上的映射比较
val people = List(Person(name = "Joe"), Person(name = "Mary"))
people.map(_.name) # => returns a List
val people = List(Person(name = "Joe"))
people.map(_.name) # => returns a List
val people = List()
people.map(_.name) # => returns a List
与Scala的XML比较
val xml1 = <people> <person><name>Joe</name></person> <person><name>Marylin</name></person> <person><name>Erik</name></person> </people>
val xml2 = <people> <person><name>Erik</name></person> </people>
val xml3 = <people> </people>
Seq(xml1, xml2, xml3).map(_ \\ "name") foreach (x => println(s"${x.getClass}\t${x.length}\t$x"))
// OUTPUT:
// class scala.xml.NodeSeq$$anon$1 3 <name>Joe</name><name>Marylin</name><name>Erik</name>
// class scala.xml.NodeSeq$$anon$1 1 <name>Erik</name>
// class scala.xml.NodeSeq$$anon$1 0
那么为什么人们不应该期望 lift-json \\
运算符具有相同的语义呢?
文档 http://liftweb.net/api/26/api/#net.liftweb.json.package有:
XPath-like expression to query JSON fields by name. Returns all matching fields.
最佳答案
在 Json4s 中 \\
现在总是返回一个 JArray
,参见 here .
val json1 =
parse("""
|{
| "people": [{
| "name": "Joe"
| }, {
| "name": "Marilyn"
| }]
|}
""".stripMargin)
val json2 =
parse("""
|{
| "people": [{
| "name": "Joe"
| }]
|}
""".stripMargin)
println(json1 \\ "name")
// JArray(List(JString(Joe), JString(Marilyn)))
println(json2 \\ "name")
// JArray(List(JString(Joe)))
关于scala - lift-json XPath\\operator 根据 num 匹配有不同的返回类型,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21762259/