regex - 如何在 vi 中删除与正则表达式匹配的行？

Question

我有一个大文本文件，其中包含以下标题，我正试图将其删除。例如:

1 Nephi 2:13
 13 Neither did they believe that Jerusalem, that great city,
could be destroyed according to the words of the prophets. And
they were like unto the Jews who were at Jerusalem, who sought to
take away the life of my father.
1 Nephi 2:14
 14 And it came to pass that my father did speak unto them in the
valley of Lemuel, with power, being filled with the Spirit, until
their frames did shake before him. And he did confound them,
that they durst not utter against him; wherefore, they did as he
commanded them.
1 Nephi 2:15
 15 And my father dwelt in a tent.
1 Nephi 2:16

我试图删除包含“1 Nephi 2:16”的整行，所以我在 vi 中寻找一个正则表达式来匹配包含书籍和诗句引用的整行。

下面是它需要匹配的示例书和诗句组合列表

1 Nephi 2:16
Mormon 3:7
Alma 32:27
Words of Mormon 1:3

Answer 1

重复 chaos 的答案:如果你能确定任何以冒号分隔的两个数字结尾的行都是标题:

:g/.* [0-9]\+:[0-9]\+$/d