我有一个 users
表和一个 roles
具有 的表多对多 关系。这两个表连接到一个名为 的连接表。 role_user
.
This is a model of the tables and its connections.
以下是我的 Laravel 项目中的模型:
用户 namespace App;
use Illuminate\Database\Eloquent\Model;
class User extends Model
{
public function roles()
{
return $this->belongsToMany('App\Role');
}
}
角色namespace App;
use Illuminate\Database\Eloquent\Model;
class Role extends Model
{
public function users()
{
return $this->belongsToMany('App\User');
}
}
下面是 Laravel 项目中的工厂文件:
$factory->define(App\User::class, function (Faker\Generator $faker) {
return [
'name' => $faker->name,
'email' => $faker->unique()->safeEmail,
'password' => $password ?: $password = bcrypt('secret'),
];
});
$factory->define(App\Role::class, function (Faker\Generator $faker) {
return [
'role' => $faker->realText($maxNbChars = 2),
'description' => $faker->realText($maxNbChars = 20),
];
});
下面是 Laravel 项目中的种子文件:public function run()
{
factory(App\User::class, 50)->create()->each(function ($u) {
$u->roles()->save(factory(App\Role::class)->make());
});
factory(App\Role::class, 20)->create()->each(function ($u) {
$u->users()->save(factory(App\User::class)->make());
});
}
这应该填充 users
表和 roles
表但我如何去填充 role_user
table ? (我没有连接表的模型文件。)我对此很陌生,因此任何帮助将不胜感激。谢谢。
最佳答案
您可以使用 attach()
or sync()
method在多对多关系上。
有多种方法可以解决这个问题。这是其中之一:
// Populate roles
factory(App\Role::class, 20)->create();
// Populate users
factory(App\User::class, 50)->create();
// Get all the roles attaching up to 3 random roles to each user
$roles = App\Role::all();
// Populate the pivot table
App\User::all()->each(function ($user) use ($roles) {
$user->roles()->attach(
$roles->random(rand(1, 3))->pluck('id')->toArray()
);
});
关于Laravel - 播种多对多关系,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45269146/