javascript - 乱码功能大赛

Question

请记住那条关于目标的客场消息，上面写着如何:

Aoccdrnig to a rscheearch at Cmabrigde Uinervtisy, it deosn't mttaer in waht oredr the ltteers in a wrod are, the olny iprmoetnt tihng is taht the frist and lsat ltteer be at the rghit pclae. The rset can be a toatl mses and you can sitll raed it wouthit porbelm. Tihs is bcuseae the huamn mnid deos not raed ervey lteter by istlef, but the wrod as a wlohe.

无论如何，我正在尝试制作一个可以对整个页面执行此操作的功能。这个函数有一些规则。

少于 4 个字符不要理会。

非字母数字字符不算作单词的一部分。

连字符真的是两个词

如果长度 >= 4，单词一定会出现乱码(不能像原来的那样)

第一个和最后一个字符保持不变，只有中间字符出现乱码(感谢 Hersheezy)

文本应始终是随机的，并且每次运行都会产生独特的乱码

纯 javascript 并在所有文本节点上迭代

最短最甜的代码获胜。

无论如何，它似乎很容易实现，如何开始一场比赛，看看谁能写出最干净最清晰的代码来完成这项任务。随意借用而不识别我的代码(我肯定有)

如果我错过了什么，请在评论中添加。无论如何，我非常笨拙地工作，这是我展示我的低于标准的工作

DEMO

var i, j, words, textNodes, punct = /[^a-zA-Z0-9]/;

Array.prototype.shuffle = function() {
    for (var i = 0; i < this.length; i++) {
        var j = i;
        while (j == i) {
            j = Math.floor(Math.random() * this.length);
        }
        var tmp = this[i];
        this[i] = this[j];
        this[j] = tmp;
    }
    return this;
};

String.prototype.shuffle = function() {
    return this.split('').shuffle().join('');
};

function transverse(element, array) {
    if (!array) array = [];
    if (element.nodeType === 3) {
        array.push(element);
    } else {
        for (var i = 0; i < element.childNodes.length; i++) {
            transverse(element.childNodes[i], array);
        }
    }
    return array;
}

function garble(str) {
    if (!str) return '';
    str = str.trim();
    if (/-/.test(str)) {
        str = str.split('-');
        for (var i = 0; i < str.length; i++) {
            str[i] = garble(str[i]);
        }
        return str.join('-')
    }
    if (punct.test(str.charAt(0))) {
        return str.charAt(0) + garble(str.slice(1));
    }
    if (punct.test(str.charAt(str.length - 1))) {
        return garble(str.slice(0, -1)) + str.charAt(str.length - 1);
    }
    if (str.length < 4) return str;
    if (str.length === 4) return str.charAt(0) + str.charAt(2) + str.charAt(1) + str.charAt(3)
    return str.charAt(0) + str.substr(1, str.length - 2).shuffle() +
        str.charAt(str.length - 1);
}


window.onload = function() {
    textNodes = transverse(document.documentElement);
    for (i = 0; i < textNodes.length; i++) {
        words = textNodes[i].data.split(' ');
        for (j = 0; j < words.length; j++) {
            words[j] = garble(words[j]);
        }
        textNodes[i].data = words.join(' ');
    }
};

Answer 1

更新(最新) : 不要以为它可以变得更小.. DEMO
最新压缩(332):

var e=document.body.getElementsByTagName('*'),j,i,l,x,t,b;for(i=0;e[i];i++)for(j=0;b=e[i].childNodes[j];j++)if(b.nodeType==3)b.data=b.data.replace(/\w{4,}/g,function(w){if(/(^.)(\1)+$/.test(x=w.substring(1,l=w.length-1)))return w;t=w;while(t==w)t=w[0]+x.split('').sort(function(){return 0.5-Math.random()}).join('')+w[l];return t}); 

代码:

var e = document.body.getElementsByTagName('*'),
    j, i, l, x, t, b;
for (i = 0; e[i]; i++)
for (j = 0; b = e[i].childNodes[j]; j++)
if (b.nodeType == 3) b.data = b.data.replace(/\w{4,}/g, function(w) {
    if (/(^.)(\1)+$/.test(x = w.substring(1, l = w.length - 1))) return w;
    t = w;
    while (t == w)
    t = w[0] + x.split('').sort(function() {
        return 0.5 - Math.random();
    }).join('') + w[l];
    return t;
});

更新 甚至……更小……

Even smaller version
我不知道您使用的缩小器，但这必须至少 ( 编辑 108) 字节小。
压缩版(365 字节):

var e=document.body.getElementsByTagName('*'),a=[],c,j,i,l,x,t,b;for(i=0;c=e[i];i++)for(j=0;b=c.childNodes[j];j++)if(b.nodeType==3){b.data=b.data.replace(/\b[a-z0-9]{4,}\b/gi,function(w){if(/(^.)(\1)+$/.test(x=w.substring(1,l=w.length-1)))return w;t=w;while(t==w)t=w[0]+x.split('').sort(function(){return Math.floor(Math.random()*2)?1:-1}).join('')+w[l];return t})}  

代码:

var e = document.body.getElementsByTagName('*'),
    a = [],
    c, j, i, l, x, t, b;
for (i = 0; c = e[i]; i++)
for (j = 0; b = c.childNodes[j]; j++)
if (b.nodeType == 3) {
    b.data = b.data.replace(/\b[a-z0-9]{4,}\b/gi, function(w) {
        if (/(^.)(\1)+$/.test(x = w.substring(1, l = w.length - 1))) return w;
        t = w;
        while (t == w)
        t = w[0] + x.split('').sort(function() {
            return Math.floor(Math.random() * 2) ? 1 : -1;
        }).join('') + w[l];
        return t;
    });
}

编辑
NEW RULES DEMO
代码:

var fn = function(e) {
    var ret = [],c;
    for (var i = 0; i < e.length; i++) {
        c = e[i].childNodes;
        for (var j = 0; j < c.length; j++)
            if (c[j].nodeType === 3) ret.push(c[j]);
    }
    return ret;
};
var es = fn(document.body.getElementsByTagName('*'));
for (var i = 0; i < es.length; i++) {
    var e = es[i],len,x;
    e.data = e.data.replace(/\b[a-z0-9]{4,}\b/gi, function(w) {
        if (/(^.)(\1)+$/.test(x = w.substring(1, len = w.length - 1))) return w;
        var tmp = w;
        while (tmp === w) {
            tmp = w[0] + x.split('').sort(function() {
                return Math.floor(Math.random() * 2) ? 1 : -1;
            }).join('') + w[len];
        }
        return tmp;
    });
}

这应该尊重所有规则，并保持格式和标点符号。 DEMO

//select all nodes in document and perform map on it to filter out
//non text node types, then each one of those elements is processed.
$('*').contents().map(function(i, elem) {
    if (elem.nodeType !== 3) return null;
    else return elem;
}).each(function(i, elem) {
 //call strip funciton defined down to get an object, with a word array, and
 //charecters which was stripped along with there index in the orginal string
    var str1 = '',
        tmp = strip(elem.data),
        words = tmp.words,
        sentence;
    // shuffle all words
    words = $.map(words, function(x, i) {
        return shuffle(x);
    });
    //construct raw sentence (non alphanumeric charecters)
    sentence = words.join('');
    //reinsert spaces and punctiouation 
    $.each(tmp.chars, function(i, elem) {
        sentence = sentence.substring(0, elem.index) + elem.char + sentence.substring(elem.index - 1 + elem.char.length);
    });
    //set the element text
    elem.data = sentence;
});

//shuffle funciton takes a word and shuffle the charecters between the last and the firt
function shuffle(txt) {
    //if the word is smaller than 4 charecters or it has repeated charecters in
    //its middle (i.e. loop, 'oo' cannot be shuffled!) then return it;
    if (txt.length < 4 || /(^.)(\1)+$/.test(txt.substring(1, txt.length - 1)))
        return txt;
    var str = txt.split(''),
        ret = [],
        rand, x = 0,
        tmp = txt;
    //while the txt hasn't changed in the first randomization cycle then repeated
    while (txt === tmp) {
        ret = [];
        $.each(str, function(i, c) {
            if (i === str.length - 1 || i === 0) {
                ret[i] = c;
                return;
            }
            while (true) {
                rand = Math.floor(Math.random() * (str.length - 2) + 1);
                if (!ret[rand]) {
                    ret[rand] = c;
                    break;
                }
            }
        });
        tmp = ret.join('');
    }
    return ret.join('');
}

function strip(txt) {
    var punc = /[^A-Za-z0-9]/g,
        res, nonAlphaNum = [],
        arr;
    //punc regex is all non-alphanumeric charecters which will act on the string
    //to point out unwanted charecters and store them in an array along with
    //their index
    while ((res = punc.exec(txt)) != null) {
        nonAlphaNum.push({
            index: res.index,
            char: res[0]
        });
    }
    //split into words
    arr = txt.split(/\s/);
    //remove punctiuation and other unwanted chars
    arr = $.map(arr, function(x, i) {
        return x.replace(punc, '');
    });
    return {
        words: arr,  //words array
        chars: nonAlphaNum //array of stripped charecter objects (chars, index in orginal)
    };
} 

顺便说一句，这篇文章的不错选择，WWiWieikikb!