我想用JSONPath解析:
[
[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],
[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
]
你能帮忙吗？
最佳答案
如果对象是:
[
[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4],
[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
]
然后
"$[0]"将返回:[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4]
然后
"$[1]"将返回:[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
您也可以在两个层次上进行操作。
"$[0][4]"将返回:205
您还可以使用
"$[*]"将数组的元素提取到列表中，这将返回2个元素的列表。第一个是:[50.4154134372953,-1.28486558931069,"CLASS B",9,205,0,"UK",431500382,3,4]
第二个是:
[50.3058858494047,-0.976070494820637,"CLASS B",9,239,0,"UK",2750350,21,2]
关于arrays - 使用JSONPATH解析JSON数组文件，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/9291435/