我有一个数据框,记录了 19717 人通过多项选择题选择编程语言的 react 。第一列当然是受访者的性别,其余的是他们选择的选项。数据框如下所示,每个响应都记录为与列相同的名称。如果没有选择响应,则结果为 NaN
.
ID Gender Python Bash R JavaScript C++
0 Male Python nan nan JavaScript nan
1 Female nan nan R JavaScript C++
2 Prefer not to say Python Bash nan nan nan
3 Male nan nan nan nan nan
我想要的是一个基于 Gender
返回计数的表.因此,如果 5000 名男性用 Python 编码,3000 名女性用 JS 编码,那么我应该得到这个:Gender Python Bash R JavaScript C++
Male 5000 1000 800 1500 1000
Female 4000 500 1500 3000 800
Prefer Not To Say 2000 ... ... ... 860
我已经尝试了一些选项:df.iloc[:, [*range(0, 13)]].stack().value_counts()
Male 16138
Python 12841
SQL 6532
R 4588
Female 3212
Java 2267
C++ 2256
Javascript 2174
Bash 2037
C 1672
MATLAB 1516
Other 1148
TypeScript 389
Prefer not to say 318
None 83
Prefer to self-describe 49
dtype: int64
这不是如上所述的要求。这可以在 Pandas 中完成吗?
最佳答案
您可以melt
并使用 crosstab
df1 = pd.melt(df,id_vars=['ID','Gender'],var_name='Language',value_name='Choice')
df1['Choice'] = np.where(df1['Choice'] == df1['Language'],1,0)
final= pd.crosstab(df1['Gender'],df1['Language'],values=df1['Choice'],aggfunc='sum')
print(final)
Language Bash C++ JavaScript Python R
Gender
Female 0 1 1 0 1
Male 0 0 1 1 0
Prefer not to say 1 0 0 1 0
关于python - 每个变量的堆栈和返回值计数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59033379/