我有一个返回类似记录的查询。
Name Total_Case_Count User_Case_Count P_Count Rej_Count PPP_Count Active_Count
XYZ 20 10 05 02 01 02
我为此使用以下查询。
select row_number() over (order by result.USER_NAME asc) as row_index,
row_number() over (order by result.USER_NAME asc) as SERIAL_NO,
result.USER_NAME,
result.USER_ACCOUNT_ID,
MAX(Total_Case_Count) AS Total_Case_Count,
MAX(User_Case_COUNT) AS User_Case_COUNT,
MAX(Pending_Case_Count) AS Pending_Case_Count,
MAX(Rejected_Case_Count) AS Rejected_Case_Count,
MAX(Pending_For_Payment_Case_Count) AS Pending_For_Payment_Case_Count,
MAX(Active_Case_Count) AS Active_Case_Count
FROM
( SELECT
UA.USER_ACCOUNT_ID,
UA.FIRST_NAME AS USER_NAME,
NVL(PUIA.PARENT_USER_ACCOUNT_ID,C.CREATED_BY) PID,
COUNT(*) OVER () Total_Case_Count,
COUNT(*) OVER (PARTITION BY UA.USER_ACCOUNT_ID) User_Case_COUNT,
CASE
WHEN C.CASE_STATUS_ID = 2 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Pending_Case_Count,
CASE
WHEN C.CASE_STATUS_ID = 4 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Rejected_Case_Count,
CASE
WHEN C.CASE_STATUS_ID = 6 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Pending_For_Payment_Case_Count,
CASE
WHEN C.CASE_STATUS_ID In (1,3,5,7,8,9) THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Active_Case_Count
FROM CASE C
INNER JOIN CASE_STATUS CS ON CS.CASE_STATUS_ID = C.CASE_STATUS_ID
INNER JOIN SSO.PARENT_USER_IN_APPLICATION PUIA ON PUIA.APPLICATION_ID=12 AND PUIA.USER_ACCOUNT_ID=c.created_by
INNER JOIN SSO.USER_ACCOUNTS UA ON UA.USER_ACCOUNT_ID=C.CREATED_BY
INNER JOIN CASE_PARTY CP ON cp.sso_user_id=nvl(PUIA.PARENT_USER_ACCOUNT_ID,PUIA.USER_ACCOUNT_ID)
inner join sso.User_In_Types uit on uit.USER_ACCOUNT_ID = UA.USER_ACCOUNT_ID
inner join SSO.USER_TYPES ut on UT.USER_TYPE_ID = UiT.USER_TYPE_ID AND UT.APPLICATION_ID=12
where
UT.APPLICATION_ID = 12 and UT.USER_TYPE_ID = 2170
and UA.USER_ACCOUNT_ID = 2187150
and c.case_source not in (4)
) result
GROUP BY result.USER_NAME, result.USER_ACCOUNT_ID
ORDER BY USER_NAME
请查看 Active_Case_Count 列。它不会在案例中带来正在传递(1,3,5,6,7,8,9)的状态计数。它只返回任何单个案例状态的计数。
实际上这个语句并没有返回所有状态的计数
CASE
WHEN C.CASE_STATUS_ID In (1,3,5,7,8,9) THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Active_Case_Count
任何建议真的很感激。
最佳答案
尝试使用:
CASE
WHEN C.CASE_STATUS_ID In (1,3,5,7,8,9) THEN 1 ELSE 0 end as Active_Case_Count
代替:
CASE
WHEN C.CASE_STATUS_ID In (1,3,5,7,8,9) THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Active_Case_Count
和
SUM(Active_Case_Count) AS Active_Case_Count
相反:
MAX(Active_Case_Count) AS Active_Case_Count
这将计算您处于状态 (1,3,5,7,8,9) 的记录总数
关于sql-server - 获取内部案例的分析函数的计数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/31403297/