java.lang.IllegalArgumentException : Illegal character in query at index 59 异常

Question

我在做什么: 我正在尝试在 android 中进行反向地理编码

我得到的错误是: java.lang.IllegalArgumentException:索引 59 处查询中的非法字符:http://maps.google.com/maps/api/geocode/json?address=Agram , 类加罗尔, 卡纳塔克邦, 印度&sensor=false

注意:该请求在浏览器中获得 json 响应，但不是来 self 下面的类

此行出现此错误::

HttpGet httpget = new HttpGet(url);

---

JSONfunctions.java

public class JSONfunctions {

    public static JSONObject getJSONfromURL(String url) {
        InputStream is = null;
        String result = "";
        JSONObject jArray = null;

        // Download JSON data from URL
        try {
            HttpClient httpclient = new DefaultHttpClient();
            HttpGet httpget = new HttpGet(url);

            HttpResponse response = httpclient.execute(httpget);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();

        } catch (Exception e) {
            Log.e("log_tag", "Error in http connection " + e.toString());
        }

        // Convert response to string
        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            result = sb.toString();
        } catch (Exception e) {
            Log.e("log_tag", "Error converting result " + e.toString());
        }

        try {

            jArray = new JSONObject(result);
        } catch (JSONException e) {
            Log.e("log_tag", "Error parsing data " + e.toString());
        }

        return jArray;
    }
}

Answer 1

使用URLEncoder.encode()在将 address 参数 "Agram, Bengaluru, Karnataka, India" 的值放入 URL 字符串之前对其进行编码，使其变成类似于

http://maps.google.com/maps/api/geocode/json?address=Agram,+Bengaluru,+Karnataka,+India&sensor=false

即空格更改为 +，其他特殊八位字节表示为 %xx。

浏览器会自动对地址栏中输入的字符串进行智能 URL 编码，这就是它在那里工作的原因。