Desc: 在 html 表中我有:
2列要输入的数据:(示例中插入了示例值，您必须自己输入才能使脚本工作)
a) start,//用户输入这个字段
b) 结束。 (信息:end 必须大于 start 才能正常工作)//用户输入此字段
4 列计算的数据/是常量:(现在正在运行)
a) 实际(结束-开始)，
b) 规范的(const，例如 8:00，在实践中不同)
c) 超时 ( = |normative - actual | (>=0) )//if actual(>)normative
d) tobeworkout ( = |normative - actual | (=<0) )//如果实际(<)normative
2 列包含我正在尝试计算的数据:(我想要实现的目标)
a) 加类天数，(如果实际>规范，则:如果开始和结束(工作时间)在 6:00(>=) 和 22:00(=<) 之间，则:加类天数 = 实际-规范)
b) overtime_night(如果 actual>normative 那么:如果开始和结束(工作时间)在 0:00 到 6:00(<) 和 22:00(>) 到 23:59 之间，那么: overtime_days = actual-规范的)
注释:
有必要考虑这种情况，例如5:00开始，20:00结束，然后计算夜间加类和白天加类:标准=8:00，从5:00到6:00=1:00 overtime_night，6:00到14: 00点正常，14:00到20:00加类_days
我做了什么？
- 我不知道如何在开始和结束之间把握时间，我正在寻找想法 , 因为这对我来说是个难题
代码:(该代码不包含对搜索值的计算)
document.querySelector('table').addEventListener('change', function (e) {
const classList = e.target.classList;
if (classList.contains('start') || classList.contains('end')) {
const tr = e.target.parentNode.parentNode;
const [start, end, actual] = [...tr.querySelectorAll('.start,.end,.actual')];
const value = diff(start.value, end.value);
actual.value = value;
}
});
document.querySelector('table').addEventListener('change', function (e) {
const classList = e.target.classList;
if (classList.contains('start') || classList.contains('end')) {
const tr = e.target.parentNode.parentNode;
const [actual, normative, overtime, tobeworkout] = [...tr.querySelectorAll('.actual,.normative,.overtime,.tobeworkout')];
if (diffMs(actual.value, normative.value) >= 0) {
overtime.value = diff(normative.value, actual.value);
tobeworkout.value = "00:00";
}
if (diffMs(actual.value, normative.value) <= 0) {
tobeworkout.value = diff(actual.value, normative.value);
overtime.value = "00:00";
}
}
});
// this function calculate a difference for a logical purposes
function diffMs(start, end) {
return +start.split(":").join('') - +end.split(":").join('');
}
function msToTime(duration) {
const minutes = Math.floor((duration / (1000 * 60)) % 60),
hours = Math.floor(duration / (1000 * 60 * 60));
return twoOrMoreDigits(hours) + ":" + twoOrMoreDigits(minutes);
}
function twoOrMoreDigits(n) {
return n < 10 ? '0' + n : n;
}
function timeToMs(time) {
if (time) { // may be "" if the value is not set
const [hours, minutes] = time.split(":").map(str => parseInt(str, 10));
return (hours * 60 + minutes) * 60 * 1000;
}
return 0;
}
function diff(start, end) {
return msToTime(timeToMs(end) - timeToMs(start));
}
<table>
<thead>
<tr>
<th>start</th>
<th>end</th>
<th>actual</th>
<th>normative</th>
<th>overtime</th>
<th>tobeworkout</th>
<th>overtime_days</th>
<th>overtime_night</th>
</tr>
</thead>
<tbody>
<tr class="day">
<td><input type="time" class="start" id="start_1" value="08:00"></td>
<td><input type="time" class="end" id="end_1" value="15:00"></td>
<td><input type="time" class="actual" id="actual_1" value="07:00" readonly></td>
<td><input type="time" class="normative" id="normative_1" value="08:00" readonly></td>
<td><input type="time" class="overtime" id="overtime_1" value="00:00" readonly></td>
<td><input type="time" class="tobeworkout" id="tobeworkout_1" value="00:00" readonly></td>
<td><input type="time" class="overtime_days" id="overtime_days_1" value="00:00" readonly></td>
<td><input type="time" class="overtime_night" id="overtime_night_1" value="00:00" readonly></td>
</tr>
<tr class="day">
<td><input type="time" class="start" id="start_2" value="08:00"></td>
<td><input type="time" class="end" id="end_2" value="17:00"></td>
<td><input type="time" class="actual" id="actual_2" value="09:00" readonly></td>
<td><input type="time" class="normative" id="normative_2" value="08:00" readonly></td>
<td><input type="time" class="overtime" id="overtime_2" value="00:00" readonly></td>
<td><input type="time" class="tobeworkout" id="tobeworkout_2" value="00:00" readonly></td>
<td><input type="time" class="overtime_days" id="overtime_days_2" value="00:00" readonly></td>
<td><input type="time" class="overtime_night" id="overtime_night_2" value="00:00" readonly></td>
</tr>
</tbody>
</table>注意事项:
请不要更改我已经编写的代码。
代码在partialView，partialView在dropdownbox(selectbox)上改变选项后刷新。
我用的是asp.net/net core 3.0
变化:!!!!
这已经改变了:(让夜晚永远是夜晚)
如果它有 normative = 08:00 和 actual = 08:00,
但他从 04:00 到 12:00(晚上从 04:00 到 6:00)工作
- 他应该将 02:00 算作夜间( 晚上 22:00 到 6:00)
好像他从 15:00 到 23:00(晚上从 22:00 到 23:00)工作
- 这应该将“overtime_night”/“additional_nigth”算作 01:00( 晚上 22:00 到 6:00)
最佳答案
如果我正确理解规则，应该这样做:
(function () { // create a closure to avoid name conficts
const table = document.querySelector('table');
const minStart = 6*60; // 06:00
const maxEnd = 22*60; // 22:00
class TimeInput {
constructor(input) {
this.input = input;
this.minutes = input.value.split(":").reduce((minutes, seconds) => minutes*60+ +seconds);
}
set value(minutes) {
this.minutes = minutes;
this.input.value = [Math.floor(minutes / 60), minutes % 60].map(i => ("0"+i).slice(-2)).join(":");
}
valueOf() {
return this.minutes;
}
}
function updateRow(row) {
let inputs = {}
for (let input of row.querySelectorAll("input")) inputs[input.className] = new TimeInput(input);
let {start, end, actual, normative, overtime, tobeworkout, overtime_days, overtime_night} = inputs;
if (!start) return; // Not a data row
actual.value = end - start; // NB: calls valueOf methods
let diff = actual - normative;
overtime.value = Math.max(0, diff);
tobeworkout.value = Math.max(0, -diff);
let workedEarly = Math.max(0, minStart - start);
let workedLate = Math.max(0, end - maxEnd);
overtime_night.value = Math.min(overtime, workedEarly + workedLate);
overtime_days.value = overtime - overtime_night;
}
table.addEventListener('change', function (e) {
updateRow(e.target.closest("TR"));
});
for (let row of table.rows) updateRow(row);
})(); // execute immediately<table>
<thead>
<tr>
<th>start</th>
<th>end</th>
<th>actual</th>
<th>normative</th>
<th>overtime</th>
<th>tobeworkout</th>
<th>overtime_days</th>
<th>overtime_night</th>
</tr>
</thead>
<tbody>
<tr class="day">
<td><input type="time" class="start" id="start_1" value="08:00"></td>
<td><input type="time" class="end" id="end_1" value="15:00"></td>
<td><input size ="5" class="actual" id="actual_1" value="07:00" readonly></td>
<td><input size ="5" class="normative" id="normative_1" value="08:00" readonly></td>
<td><input size ="5" class="overtime" id="overtime_1" value="00:00" readonly></td>
<td><input size ="5" class="tobeworkout" id="tobeworkout_1" value="00:00" readonly></td>
<td><input size ="5" class="overtime_days" id="overtime_days_1" value="00:00" readonly></td>
<td><input size ="5" class="overtime_night" id="overtime_night_1" value="00:00" readonly></td>
</tr>
<tr class="day">
<td><input type="time" class="start" id="start_2" value="08:00"></td>
<td><input type="time" class="end" id="end_2" value="17:00"></td>
<td><input size ="5" class="actual" id="actual_2" value="09:00" readonly></td>
<td><input size ="5" class="normative" id="normative_2" value="08:00" readonly></td>
<td><input size ="5" class="overtime" id="overtime_2" value="00:00" readonly></td>
<td><input size ="5" class="tobeworkout" id="tobeworkout_2" value="00:00" readonly></td>
<td><input size ="5" class="overtime_days" id="overtime_days_2" value="00:00" readonly></td>
<td><input size ="5" class="overtime_night" id="overtime_night_2" value="00:00" readonly></td>
</tr>
</tbody>
</table>我介绍了一个处理分钟和 hh:mm 表示法之间转换的类。这样，其余的代码就可以根据分钟只专注于逻辑。
注意:对于最后 6 列，我不会使用 type="time"，因为严格来说这些不是一天中的时间，而是持续时间。如果浏览器的区域设置使用 AM/PM 表示法，那么浏览器也可能会以这些值显示 AM/PM，这在考虑持续时间时毫无意义。
关于javascript - 计算其他时空之间的时间更新，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/60024957/