我已经尝试了很多关于这个话题的答案,没有人适合我。
我有一个基本的 CRUD 和 Spring MVC 4.1.7,Spring Security 3.2.3 在 MySQL + Tomcat7 上工作。
问题是,当我尝试使用 AngularJS POST 表单时,我一直被错误 403(访问被拒绝)阻止。
我发现我需要用 POST 请求发送我的 CSRF_TOKEN,但我不知道怎么做!
我尝试了很多不同的方法,但没有一个有效。
我的文件
Controller .js
$scope.novo = function novo() {
if($scope.id){
alert("Update - " + $scope.id);
}
else{
var Obj = {
descricao : 'Test',
saldo_inicial : 0.00,
saldo : 33.45,
aberto : false,
usuario_id : null,
ativo : true
};
$http.post(urlBase + 'caixas/adicionar', Obj).success(function(data) {
$scope.caixas = data;
}).error(function(data) {alert(data)});
}
};
Spring-security.xml
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security.xsd">
<!-- enable use-expressions -->
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/seguro**"
access="hasAnyRole('ROLE_USER','ROLE_ADMIN')" />
<intercept-url pattern="/seguro/financeiro**"
access="hasAnyRole('ROLE_FINANCEIRO','ROLE_ADMIN')" />
<!-- access denied page -->
<access-denied-handler error-page="/negado" />
<form-login login-page="/home/" default-target-url="/seguro/"
authentication-failure-url="/home?error" username-parameter="inputEmail"
password-parameter="inputPassword" />
<logout logout-success-url="/home?logout" />
<!-- enable csrf protection -->
<csrf />
</http>
<!-- Select users and user_roles from database -->
<authentication-manager>
<authentication-provider>
<password-encoder hash="md5" />
<jdbc-user-service data-source-ref="dataSource"
users-by-username-query="SELECT login, senha, ativo
FROM usuarios
WHERE login = ?"
authorities-by-username-query="SELECT u.login, r.role
FROM usuarios_roles r, usuarios u
WHERE u.id = r.usuario_id
AND u.login = ?" />
</authentication-provider>
</authentication-manager>
网页.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<display-name>Barattie ~ Soluções Integradas</display-name>
<!-- The definition of the Root Spring Container shared by all Servlets
and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring/spring-security.xml
/WEB-INF/spring/spring-database.xml
/WEB-INF/spring/spring-hibernate.xml
</param-value>
</context-param>
<context-param>
<param-name>com.sun.faces.writeStateAtFormEnd</param-name>
<param-value>false</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/home</url-pattern>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<error-page>
<exception-type>java.lang.Throwable</exception-type>
<location>/erro</location>
</error-page>
更新
我试图在客户端添加重命名 xsrf,但我一直拒绝访问。
var app = angular.module('myApp', []).config(function($httpProvider) {
$httpProvider.defaults.xsrfCookieName = '_csrf';
$httpProvider.defaults.xsrfHeaderName = 'X-CSRF-Token';
});
** 更新 2 **
我试图实现这样的过滤器。
package sys.barattie.util;
import java.io.IOException;
import javax.servlet.FilterChain;
import javax.servlet.ServletException;
import javax.servlet.http.Cookie;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.security.web.csrf.CsrfToken;
import org.springframework.web.filter.OncePerRequestFilter;
public class CsrfFilter extends OncePerRequestFilter {
@Override
protected void doFilterInternal(HttpServletRequest request, HttpServletResponse response, FilterChain filterChain)
throws ServletException, IOException {
CsrfToken csrf = (CsrfToken) request.getAttribute(CsrfToken.class.getName());
if (csrf != null) {
Cookie cookie = new Cookie("XSRF-TOKEN", csrf.getToken());
cookie.setPath("/");
response.addCookie(cookie);
}
filterChain.doFilter(request, response);
}
}
并将我的 Spring 安全更改为它。
<csrf token-repository-ref="csrfTokenRepository" />
<beans:bean id="csrfTokenRepository" class="org.springframework.security.web.csrf.HttpSessionCsrfTokenRepository">
<beans:property name="headerName" value="X-XSRF-TOKEN" />
</beans:bean>
网页.xml
<filter>
<filter-name>csrfFilter</filter-name>
<filter-class>sys.barattie.util.CsrfFilter</filter-class>
</filter>
但是好像服务器没有运行过滤器,我给它添加了一个 System.out.println ,但是在调试中看不到消息
最佳答案
我做了一些测试,最终得到了这个。
在我的登录 Controller 中,如果我的用户身份验证成功,我会创建一个名称为 AngularJS token 的 token ,就像这样。
CsrfToken csrf = (CsrfToken) request.getAttribute(CsrfToken.class.getName());
if (csrf != null) {
Cookie cookie = new Cookie("XSRF-TOKEN", csrf.getToken());
cookie.setPath("/");
response.addCookie(cookie);
}
之后,我可以成功管理我的 $http.post。
我不知道这是否是最好的方法,但这是对我有用的方法!
感谢@Joao Evangelista 的帮助
关于angularjs - Spring CSRF + AngularJs,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31389120/