json - 如何在Pure Batch中解析JSon

Question

我试图了解批处理文件中的for循环如何使用/ F“ delims =”选项但不带令牌地遍历所有项。我尝试了各种方法，但是失败了。首先，我知道还有其他方法可以读取json文件，但我只想了解如何在不使用任何外部程序jscript jq等的情况下以纯批处理方式进行读取。JSon格式如下所示，但项目数和顺序他们倾向于变化。

{"SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString"}
{"SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString"}
{"SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString"}
{"SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString", "SomeVariableName": "SomeString"}
etc

但有时可能只是：

"SomeVariableName2": "SomeString2", "SomeVariableName1": "SomeString1",

例如，我已经完成了：

SetLocal DisableDelayedExpansion
For /F "delims=" %%c (file.json) Do(
REM iterate through each line
  set "Line=%%c"
  setlocal EnableDelayedExpansion
  set CR=CRLFCRLF
  Set "LineChange1=!Line:~1,-1!"
  for %%d in ("!CR!") do set LineChange2=!LineChange1:", "=%%~d!
  for %%e in (!LineChange4:CRLFCRLF= !) do set /a numtkns+=1
  REM but don't know how to insert the above numtkns in for options as it seems to require a function.
  set LineChange3=!LineChange2:": "==!
  set LineChange4=!LineChange3:"=!
  set /A Countr+=1
  REM this leaves this current line stored in variable LineChange4 as SomeVariableName=SomeStringCRLFCRLFSomeVariableName=SomeStringCRLFCRLFSomeVariableName=SomeStringCRLFCRLFSomeVariableName=SomeString
  )

或者，我可以使用换行符代替CRLFCRLF：

SetLocal DisableDelayedExpansion
For /F "delims=" %%c (file.json) Do(
REM iterate through each line
set "Line=%%c"
setlocal EnableDelayedExpansion
for /f %%d in ('copy /Z "%~dpf0" nul') do (
 set "CR=%%d"
)
Set "LineChange1=!Line:~1,-1!"
for %%e in ("!CR!") do set LineChange2=!LineChange1:", "=%%~e!
set LineChange3=!LineChange2:": "==!
set LineChange4=!LineChange3:"=!
set /A Countr+=1

)

这导致多行存储在变量LineChange4中：

SomeVariableName=SomeString
SomeVariableName=SomeString
SomeVariableName=SomeString
SomeVariableName=SomeString

如何迭代每个键值对并将每个值分配给与键名称相同的变量。我看过另一篇文章，他们确实设置了var_％SomeVariableName％= SomeString，但它仅适用于第一个键值对，并且我希望它遍历所有项直到最后一个项，即使令牌的数量和顺序有所不同。

编辑：SomeString可能是带有各种字符的标题，因此唯一近似的已知值是SomeVariableName键，这些键通常没有空格。

Edit2：我最初并没有添加，我还使用了“ Set“ LineChange1 =！Line：〜1，-1！”来删除JSon文件通常附带的花括号。

Answer 1

另一种更简单的方法：

@echo off
setlocal EnableDelayedExpansion

rem Read the lines of JSon file, removing braces
for /F "delims={}" %%a in (file.json) do (
   set "line=%%~a"
   rem Process each pair of "variable": "string" values
   for %%b in ("!line:": "==!") do echo SET %%b
)

使用此输入文件：

{"SomeVariableName1": "Some String 1", "SomeVariableName2": "Some&String<2", "SomeVariableName3": "Some>String|3", "SomeVariableName4": "Some  String  4"}
{"SomeVariableName1": "SomeString1", "SomeVariableName2": "SomeString2", "SomeVariableName3": "SomeString3", "SomeVariableName4": "SomeString4"}
{"SomeVariableName1": "SomeString1", "SomeVariableName2": "SomeString2", "SomeVariableName3": "SomeString3", "SomeVariableName4": "SomeString4"}
{"SomeVariableName1": "SomeString1", "SomeVariableName2": "SomeString2", "SomeVariableName3": "SomeString3", "SomeVariableName4": "SomeString4"}

...这是输出：

SET "SomeVariableName1=Some String 1"
SET "SomeVariableName2=Some&String<2"
SET "SomeVariableName3=Some>String|3"
SET "SomeVariableName4=Some  String  4"
SET "SomeVariableName1=SomeString1"
SET "SomeVariableName2=SomeString2"
SET "SomeVariableName3=SomeString3"
SET "SomeVariableName4=SomeString4"
SET "SomeVariableName1=SomeString1"
SET "SomeVariableName2=SomeString2"
SET "SomeVariableName3=SomeString3"
SET "SomeVariableName4=SomeString4"
SET "SomeVariableName1=SomeString1"
SET "SomeVariableName2=SomeString2"
SET "SomeVariableName3=SomeString3"
SET "SomeVariableName4=SomeString4"