python - 函数在Python Tkinter中不起作用吗？

Question

我使用Python Tkinter编写了程序，在其中编写了三行10个标签，并在它们下面创建了一个开始按钮。我已使用循环在“标签”中显示文本。

标签的第一行仅显示标题。



在Label的第二行中，我设置了以下条件：如果循环值模数等于零(a%2==0)，则将Labels文本显示为ON，否则显示OFF，并且此条件在Label的第三行中与以下代码相反。



最终，在启动按钮上，我调用了一个函数，该函数验证以下过程：如果循环变量值模数2等于1，则在“标签”的第二行显示“标签”文本为“ OFF”，否则为“ ON”。此过程与“标签”的第三行相反。但是这里的问题是，当我单击“开始”按钮时，它仅更改了标签第二行和第三行的最后一个值，但我想更改所有标签。我认为这些功能无法正常工作。代码如下。

from tkinter import *
import tkinter as tk

win = Tk()
win.title("Label")
win.geometry("800x600+50+50")
win.config(bg='white')

label1=Label(win, text="Label Status Changer", font=("Calibri",24,"bold"), bg='white', borderwidth=1, relief="solid", padx=20, pady=20) #"flat", "raised", "sunken", "ridge", "solid", and "groove"
label1.pack(pady=(15,60))


lblframe = tk.Frame(win)
for a1 in range(10):
    pre1=Label(lblframe, text=("LBL",(a1+1)), font=("Calibri",12, "bold"), bg="white", borderwidth=1, relief="solid", padx=5, pady=2)
    pre1.grid(row=0, column=a1)

for a2 in range(10):
    if ( a2%2 == 0 ):
        pre2=Label(lblframe, text="OFF", font=("Calibri",12,"bold"), bg="white", fg="Green", borderwidth=1, relief="solid", padx=11, pady=1)
        pre2.grid(row=1, column=a2, sticky="nw")
    else:
        pre2=Label(lblframe, text="ON", font=("Calibri",12,"bold"), bg="white", fg="Red", borderwidth=1, relief="solid", padx=11, pady=1)
        pre2.grid(row=1, column=a2, sticky="nw")

for a3 in range(10):
    if (a3%2 == 1):
        pre3=Label(lblframe, text="OFF", font=("Calibri",12,"bold"), bg="white", fg="Green", borderwidth=1, relief="solid", padx=11, pady=1)
        pre3.grid(row=2, column=a3, sticky="nw")
    else:
        pre3=Label(lblframe, text="ON", font=("Calibri",12,"bold"), bg="white", fg="Red", borderwidth=1, relief="solid", padx=11, pady=1)
        pre3.grid(row=2, column=a3, sticky="nw")

lblframe.pack()

def oldstatus():
    for a4 in range(10):
        if(a4%2==1):
            pre2.config(text="OFF")
        else:
            pre2.config(text="ON")

def newstatus():
    for a5 in range(10):
        if(a5%2==0):
            pre3.config(text="OFF")
        else:
            pre3.config(text="ON")

def statuschanger():
    oldstatus()
    newstatus()

#Button1
button1=Button(win,text="Start",width=10,height=2, font=("Calibri",16,"bold"), bg="black",fg="white", command=statuschanger)
button1.pack(pady=(30,0))

win.mainloop()

运行程序输出



按下开始按钮时输出

Answer 1

有用：

from tkinter import *
import tkinter as tk

win = Tk()
win.title("Label")
win.geometry("800x600+50+50")
win.config(bg='white')

label1=Label(win, text="Label Status Changer", font=("Calibri",24,"bold"), bg='white', borderwidth=1, relief="solid", padx=20, pady=20) #"flat", "raised", "sunken", "ridge", "solid", and "groove"
label1.pack(pady=(15,60))

list1=[]
list2=[]

lblframe = tk.Frame(win)
for a1 in range(10):
    pre1=Label(lblframe, text=("LBL",(a1+1)), font=("Calibri",12, "bold"), bg="white", borderwidth=1, relief="solid", padx=5, pady=2)
    pre1.grid(row=0, column=a1)

for l1 in range(10):
    if l1%2 ==0:
        list1.append(1)
    else:
        list1.append(0)

print(list1)
for l2 in range(10):
    if l2%2 ==1:
        list2.append(1)
    else:
        list2.append(0)
print(list2)

def mylabels():
    for a2 in range(10):
        if ( int(list1[a2])== 0 ):
            pre2=Label(lblframe, text="OFF", font=("Calibri",12,"bold"), bg="white", fg="Green", borderwidth=1, relief="solid", padx=11, pady=1)
            pre2.grid(row=1, column=a2, sticky="nw")
            #list1.append(pre2.cget("text"))
        else:
            pre2=Label(lblframe, text="ON", font=("Calibri",12,"bold"), bg="white", fg="Red", borderwidth=1, relief="solid", padx=11, pady=1)
            pre2.grid(row=1, column=a2, sticky="nw")
            #list1.append(pre2.cget("text"))

    for a3 in range(10):
        if (int(list2[a3])== 0):
            pre3=Label(lblframe, text="OFF", font=("Calibri",12,"bold"), bg="white", fg="Green", borderwidth=1, relief="solid", padx=11, pady=1)
            pre3.grid(row=2, column=a3, sticky="nw")
            #list2.append(pre3.cget("text"))
        else:
            pre3=Label(lblframe, text="ON", font=("Calibri",12,"bold"), bg="white", fg="Red", borderwidth=1, relief="solid", padx=11, pady=1)
            pre3.grid(row=2, column=a3, sticky="nw")
            #list2.append(pre3.cget("text"))

lblframe.pack()

mylabels()

def statuschanger():
    list1.clear()
    list2.clear()
    for l3 in range(10):
        if l3%2 ==1:
            list1.append(1)
        else:
            list1.append(0)

    for l4 in range(10):
        if l4%2 ==0:
            list2.append(1)
        else:
            list2.append(0)
    mylabels()


#Button1
button1=Button(win,text="Start",width=10,height=2, font=("Calibri",16,"bold"), bg="black",fg="white", command=statuschanger)
button1.pack(pady=(30,0))

win.mainloop()

运行编程时输出



按下开始按钮时输出