是否可以在原始函数内使用外部变量?
$var = 'example';
$res = DB::collection("{$var}_products")->raw(function($collection) {
global $var;
return $collection->aggregate([
['$lookup' => [
'from' => "{$var}_specifications",
'localField' => 'specifications_id',
'foreignField' => '_id',
'as' => 'specifications'
]]
]);
});
我只找到了一个普通 SQL 的示例 ( https://fideloper.com/laravel-raw-queries )
$someVariable = Input::get("some_variable");
$results = DB::select( DB::raw("SELECT * FROM some_table WHERE some_col = :somevariable"), array(
'somevariable' => $someVariable,
));
最佳答案
像这样在函数闭包中使用变量
$var = 'example';
$res = DB::collection("{$var}_products")->raw(function($collection) use ($var) {
return $collection->aggregate([
['$lookup' => [
'from' => "{$var}_specifications",
'localField' => 'specifications_id',
'foreignField' => '_id',
'as' => 'specifications'
]]
]);
});
关于php - Laravel mongodb 聚合,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58034522/