在 LLDB 中,如何实现函数步/跟踪步?也就是说,继续执行,直到调用函数或返回当前函数。假设直到
都没有可用的源代码来执行。
这相当于执行step-inst
直到堆栈帧结构发生变化。
最佳答案
这是一个针对 lldb 的 Python 脚本,其中添加了“step-function”命令。只要调用堆栈结构发生变化,该命令就会停止。
step_func.py
import lldb
def step_func(debugger, command, result, internal_dict):
thread = debugger.GetSelectedTarget().GetProcess().GetSelectedThread()
start_num_frames = thread.GetNumFrames()
if start_num_frames == 0:
return
while True:
thread.StepInstruction(0)
if thread.GetNumFrames() != start_num_frames:
stream = lldb.SBStream()
thread.GetStatus(stream)
description = stream.GetData()
print >>result, "Call stack depth changed %d -> %d" % (start_num_frames, thread.GetNumFrames())
print >>result, description,
break
def __lldb_init_module (debugger, dict):
debugger.HandleCommand('command script add -f %s.step_func sf' % __name__)
使用示例:
$ lldb /bin/ls
Current executable set to '/bin/ls' (x86_64).
(lldb) command script import step_func (lldb) process launch --stop-at-entry Process 12944 launched: '/bin/ls' (x86_64)
Process 12944 stopped
* thread #1: tid = 0x438b0, 0x00007fff5fc01028 dyld`_dyld_start, stop reason = signal SIGSTOP
frame #0: 0x00007fff5fc01028 dyld`_dyld_start
dyld`_dyld_start:
-> 0x7fff5fc01028: popq %rdi
0x7fff5fc01029: pushq $0
0x7fff5fc0102b: movq %rsp, %rbp
0x7fff5fc0102e: andq $-16, %rsp
(lldb) sf
Call stack depth changed 1 -> 2
* thread #1: tid = 0x438b0, 0x00007fff5fc0109e dyld`dyldbootstrap::start(macho_header const*, int, char const**, long, macho_header const*, unsigned long*), stop reason = instruction step into
frame #0: 0x00007fff5fc0109e dyld`dyldbootstrap::start(macho_header const*, int, char const**, long, macho_header const*, unsigned long*)
dyld`dyldbootstrap::start(macho_header const*, int, char const**, long, macho_header const*, unsigned long*):
-> 0x7fff5fc0109e: pushq %rbp
0x7fff5fc0109f: movq %rsp, %rbp
0x7fff5fc010a2: pushq %r15
0x7fff5fc010a4: pushq %r14
(lldb)
Call stack depth changed 2 -> 3
* thread #1: tid = 0x438b0, 0x00007fff5fc22f9b dyld`mach_init, stop reason = instruction step into
frame #0: 0x00007fff5fc22f9b dyld`mach_init
dyld`mach_init:
-> 0x7fff5fc22f9b: pushq %rbp
0x7fff5fc22f9c: movq %rsp, %rbp
0x7fff5fc22f9f: movb 326075(%rip), %al ; mach_init.mach_init_inited
0x7fff5fc22fa5: testb %al, %al
(lldb)
Call stack depth changed 3 -> 4
* thread #1: tid = 0x438b0, 0x00007fff5fc22fb9 dyld`mach_init_doit, stop reason = instruction step into
frame #0: 0x00007fff5fc22fb9 dyld`mach_init_doit
dyld`mach_init_doit:
-> 0x7fff5fc22fb9: pushq %rbp
0x7fff5fc22fba: movq %rsp, %rbp
0x7fff5fc22fbd: callq 0x7fff5fc23210 ; task_self_trap
0x7fff5fc22fc2: movl %eax, 69740(%rip) ; mach_task_self_
(lldb)
Call stack depth changed 4 -> 5
* thread #1: tid = 0x438b0, 0x00007fff5fc23210 dyld`task_self_trap, stop reason = instruction step into
frame #0: 0x00007fff5fc23210 dyld`task_self_trap
dyld`task_self_trap:
-> 0x7fff5fc23210: movq %rcx, %r10
0x7fff5fc23213: movl $16777244, %eax
0x7fff5fc23218: syscall
0x7fff5fc2321a: ret
(lldb)
Call stack depth changed 5 -> 4
* thread #1: tid = 0x438b0, 0x00007fff5fc22fc2 dyld`mach_init_doit + 9, stop reason = instruction step into
frame #0: 0x00007fff5fc22fc2 dyld`mach_init_doit + 9
dyld`mach_init_doit + 9:
-> 0x7fff5fc22fc2: movl %eax, 69740(%rip) ; mach_task_self_
0x7fff5fc22fc8: callq 0x7fff5fc231f8 ; mach_reply_port
0x7fff5fc22fcd: leaq 69724(%rip), %rcx ; _task_reply_port
0x7fff5fc22fd4: movl %eax, (%rcx)
(lldb)
关于debugging - lldb 命令到函数步/跟踪步 : continue until next function call or until current function is returned from,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22009815/