我有一个字符串数组 pointAddress
,我想检查每个条目是否包含来自另一个数组 validPointTypes
的字符串。
def pointAddress = ['bacnet://240101/AV:3', 'bacnet://240101/BV:9', 'bacnet://240101/AV:7', 'bacnet://240101/BALM:15']
def validPointTypes = ['AV', 'AI', 'AO', 'ANI', 'ANO', 'BV', 'BI', 'BO', 'BNI', 'BNO']
现在我只有一个巨大的 if
语句。
j = pointName.size()
for(j=j-1; j>=0;j--) {
if(pointAddress[j]) {
if(pointAddress[j].contains('AV') || pointAddress[j].contains('AI') ||
pointAddress[j].contains('AO') || pointAddress[j].contains('ANI') ||
pointAddress[j].contains('ANO') || pointAddress[j].contains('BV') ||
pointAddress[j].contains('BI') || pointAddress[j].contains('BO') ||
pointAddress[j].contains('BNI') || pointAddress[j].contains('BNO')) {
} else {
pointAddress.remove(j)
pointName.remove(j)
m++
}
} else {
pointName.remove(j)
m++
}
}
一定有更好的方法,对吧?
最佳答案
def valid = pointAddress.findAll { a ->
validPointTypes.any { a.contains(it) }
}
应该这样做
关于arrays - Groovy:如何检查字符串是否包含数组的任何元素?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27069701/