我在 Table1 中有一个列,其中包含用逗号分隔的字符串:
Id Val
1 ,4
2 ,3,1,0
3 NULL
4 ,5,2
有没有一种简单的方法可以拆分并从该列中获取任何值, 例如
SELECT Value(1) FROM Table1 应该得到 p>
Id Val
1 4
2 3
3 NULL
4 5
SELECT Value(2) FROM Table1 应该得到 p>
Id Val
1 NULL
2 1
3 NULL
4 2
谢谢!
最佳答案
在列中存储逗号分隔值总是很痛苦,请考虑更改表结构
要完成此操作,请创建一个分割字符串函数。这是将字符串拆分为单独行的最佳方法之一。引用自http://www.sqlservercentral.com/articles/Tally+Table/72993/
CREATE FUNCTION [dbo].[DelimitedSplit8K]
(@pString VARCHAR(8000), @pDelimiter CHAR(1))
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 0 up to 10,000...
-- enough to cover NVARCHAR(4000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(@pString, l.N1, l.L1)
FROM cteLen l
调用函数
SELECT *
FROM yourtable
CROSS apply (SELECT CASE WHEN LEFT(val, 1) = ',' THEN Stuff(val, 1, 1, '') ELSE val END) cs (cleanedval)
CROSS apply [dbo].[Delimitedsplit8k](cs.cleanedval, ',')
WHERE ItemNumber = 1
SELECT *
FROM yourtable
CROSS apply (SELECT CASE WHEN LEFT(val, 1) = ',' THEN Stuff(val, 1, 1, '') ELSE val END) cs (cleanedval)
CROSS apply [dbo].[Delimitedsplit8k](cs.cleanedval, ',')
WHERE ItemNumber = 2
关于sql - MS SQL Server 获取逗号之间的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48240404/