oracle - 无过程/函数/签名

Question

我在使用存储过程方面相对较新，而且我真的已经碰壁了。我使用 Spring JdbcTemplate 收到以下错误消息。我的开发环境是Xubuntu，jdk 1.8。

堆栈跟踪是:

Exception in thread "main" org.springframework.dao.InvalidDataAccessApiUsageException: Unable to determine the correct call signature - no procedure/function/signature for 'PROCONEINPARAMETER'
  at org.springframework.jdbc.core.metadata.GenericCallMetaDataProvider.processProcedureColumns(GenericCallMetaDataProvider.java:347)
  at org.springframework.jdbc.core.metadata.GenericCallMetaDataProvider.initializeWithProcedureColumnMetaData(GenericCallMetaDataProvider.java:112)
  at org.springframework.jdbc.core.metadata.CallMetaDataProviderFactory$1.processMetaData(CallMetaDataProviderFactory.java:133)
  at org.springframework.jdbc.support.JdbcUtils.extractDatabaseMetaData(JdbcUtils.java:299)
  at org.springframework.jdbc.core.metadata.CallMetaDataProviderFactory.createMetaDataProvider(CallMetaDataProviderFactory.java:73)
  at org.springframework.jdbc.core.metadata.CallMetaDataContext.initializeMetaData(CallMetaDataContext.java:286)
  at org.springframework.jdbc.core.simple.AbstractJdbcCall.compileInternal(AbstractJdbcCall.java:303)
  at org.springframework.jdbc.core.simple.AbstractJdbcCall.compile(AbstractJdbcCall.java:288)
  at org.springframework.jdbc.core.simple.AbstractJdbcCall.checkCompiled(AbstractJdbcCall.java:348)
  at org.springframework.jdbc.core.simple.AbstractJdbcCall.doExecute(AbstractJdbcCall.java:375)
  at org.springframework.jdbc.core.simple.SimpleJdbcCall.executeFunction(SimpleJdbcCall.java:153)
  at test.jdbc.StringDao.executeProcOneINParameter(StringDao.java:21)
  at test.jdbc.SimpleJdbcTest.main(SimpleJdbcTest.java:15)

代码:

SimpleJdbc.java

package test.jdbc;
import java.util.Map;

import org.springframework.context.ApplicationContext;  
import org.springframework.context.support.ClassPathXmlApplicationContext;  
public class SimpleJdbcTest {



    public static void main(String[] args) {  
        ApplicationContext ctx=new ClassPathXmlApplicationContext("applicationContext.xml");  
           StringDao dao=(StringDao)ctx.getBean("edao");  
        String request = new String(" Wow, this works!");

        String response = dao.executeProcOneINParameter(request);  
        if (response != null && !response.equals(new String())) {
            System.out.println("stored proc worked: "+ response);

        } else {
            System.err.println("stored proc did not work.");
        }
    }  

}

StringDao.java

package test.jdbc;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.simple.SimpleJdbcCall;

public class StringDao {

    private static final String PROC_NAME = "PROCONEINPARAMETER";
    private static final String CAT_NAME = "LISTENER";
    private JdbcTemplate jdbcTemplate;

    public void setJdbcTemplate(JdbcTemplate jdbcTemplate) {
        this.jdbcTemplate = jdbcTemplate;
    }

    public String executeProcOneINParameter(String callParam){
        SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
                .withCatalogName(CAT_NAME)
                .withProcedureName(PROC_NAME);

        return jdbcCall.executeFunction(String.class, callParam);
    }

}

存储过程:

PROCONEINPARAMETER

CREATE OR REPLACE PROCEDURE procOneINParameter(param1 IN VARCHAR2)
IS
BEGIN

  DBMS_OUTPUT.PUT_LINE('Hello World IN parameter ' || param1);

END;

Answer 1

除了@Alex 发布并我更正的问题之外，最终的问题如下:

static final String PROC_NAME = "PROCONEINPARAMETER";
private static final String CAT_NAME = "LISTENER";

…..
SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
            .withCatalogName(CAT_NAME)
            .withProcedureName(PROC_NAME);

而不是:

SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
            .withSchemaName(CAT_NAME)
            .withProcedureName(PROC_NAME);

显然，任何人都无法知道我正在交替使用目录和架构名称。