我使用以下查询来获取 Laravel 中特定表的项目 Id 和 Id。
$projectlist = Projects::Where('customer',$request->input('client_name'))->pluck(DB::raw("CONCAT('project_prefix','project_nos') AS projectid"),"id");
我收到以下错误。
message Illegal offset type in isset or empty
exception ErrorException
file /var/www/msstone/vendor/laravel/framework/src/Illuminate/Support/Str.php
项目模型
namespace App;
use Illuminate\Database\Eloquent\Model;
class Projects extends Model
{
protected $guarded = ['id'];
protected $table = 'projects';
}
最佳答案
尝试更改 Eloquent 查询:
$projectlist=Projects::Where('customer',$request->input('client_name'))->pluck(DB::raw("CONCAT('project_prefix','project_nos') AS projectid"),"id");
至
$projectlist = Projects::select(DB::raw("CONCAT(project_prefix,project_nos) AS projectid"),'id')->where('customer',$request->input('client_name'))->pluck("projectid","id");
关于laravel - isset 或空 Laravel 中的偏移类型非法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57105967/