excel - 如何从Excel列字母中获取列号(或索引)

Question

我已经搜索过这个网站并用谷歌搜索了一个公式。我需要根据字母计算 Excel 列号，例如:

A=1
B=2
..
AA=27
AZ=52
...
AAA=703

The code seems to be 1 digit off after random cycles of the alphabet(AZ -> BA == off digit). It also will seemingly randomly produce the same integer from two different inputs:

GetColumnNumber(xlLetter : Text) : Integer //Start of function

 StringLength := STRLEN(xlLetter);
 FOR i := 1 TO StringLength DO BEGIN
 Letter := xlLetter[i];
   IF i>1 THEN
     Count += ((xlLetter[i-1]-64) * (i-1) * 26) - 1;
   Count += (Letter - 64);
 END;
 EXIT(Count); //return value

我的代码示例是用 C/AL 编写的，用于 Dynamics NAV，但我也可以编写 C# 或 vb.net，因此我不介意示例使用这两种语言中的任何一种。

Answer 1

在 VBA 中:

Public Function GetCol(c As String) As Long
    Dim i As Long, t As Long
    c = UCase(c)
    For i = Len(c) To 1 Step -1
        t = t + ((Asc(Mid(c, i, 1)) - 64) * (26 ^ (Len(c) - i)))
    Next i
    GetCol = t
End Function