我有以下结构,需要将其合并到单个字典列表中。
我可以更改 secrets
列表的语法/结构(如果更容易的话,可以更改为其他内容)。
vars:
users:
- name: foo
database: foodb
- name: bar
database: bardb
secrets:
- name: foo
password: foopass
- name: bar
password: barpass
预期结果:
users:
- name: foo
database: foodb
password: foopass
- name: bar
database: bardb
password: barpass
我尝试了几种过滤器都无济于事,我最接近的是:
tasks:
- set_fact: foo: "{{ foo|default([]) + [item | combine(secrets, recursive=True)] }}"
with_items: "{{ users }}"
结果:
fatal: [localhost]: FAILED! => {"failed": true, "msg": "|combine expects dictionaries, got u'foo'"}
最佳答案
例如:
---
- hosts: localhost
gather_facts: no
vars:
users:
- name: foo
database: foodb
- name: bar
database: bardb
secrets:
- name: foo
password: foopass
- name: bar
password: barpass
tasks:
- set_fact:
tmp_user: "{{ item | combine(secrets | selectattr('name','equalto',item.name) | first) }}"
with_items: "{{ users }}"
register: tmp_users
- set_fact:
users: "{{ tmp_users.results | map(attribute='ansible_facts.tmp_user') | list }}"
- debug:
msg: "{{ users }}"
关于ansible - 追加到 Ansible 列表中的字典,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/42673166/