YouTube 数据 API v3 直接表单上传

Question

我使用 YouTube Data API v2 进行了系统设置，允许用户通过我网站上的表单将视频直接上传到我的 YouTube 帐户(我了解这意味着什么，请保留请记住，我只是对该工具的功能进行了简单的描述)。由于 v2 已弃用，到目前为止我无法弄清楚如何使用 v3 API 设置同一系统。另请注意，我希望能够在不将用户发送到 OAuth 页面的情况下执行此操作，因为我不需要访问他们的 YouTube 帐户。

这里是 PHP 代码的精简版本，使其适用于 v2:

<?php
    if ($_GET['op'] == "yt") {
        if ($_GET['status'] == "200") {
            // video upload was successful, $_GET['id'] contains the YouTube video ID for the upload
        } else {
            // video upload failed
        }
    } else {
        require_once("Zend/Loader.php");

        Zend_Loader::loadClass("Zend_Gdata_ClientLogin");
        Zend_Loader::loadClass("Zend_Gdata_YouTube");

        $httpClient = Zend_Gdata_ClientLogin::getHttpClient(
            $username       = "YOUTUBE_USERNAME",
            $password       = "YOUTUBE_PASSWORD",
            $service        = "youtube",
            $client         = null,
            $source         = "My Video Upload Bla Bla Bla",
            $loginToken     = null,
            $loginCaptcha   = null,
            "https://www.google.com/accounts/ClientLogin"
        );

        $yt = new Zend_Gdata_YouTube($httpClient, "My Video Upload Bla Bla Bla", "My Video Upload Bla Bla Bla", "YOUTUBE_DEVELOPER_KEY");
        $yt->setMajorProtocolVersion(2);

        $myVideoEntry = new Zend_Gdata_YouTube_VideoEntry();
        $myVideoEntry->setVideoTitle("Video Title");
        $myVideoEntry->setVideoDescription("Video Description");
        $myVideoEntry->setVideoCategory("People");

        $accessControlElement = new Zend_Gdata_App_Extension_Element("yt:accessControl", "yt", "http://gdata.youtube.com/schemas/2007", "");
        $accessControlElement->setExtensionAttributes(array(
            array("namespaceUri" => "", "name" => "action", "value" => "list"),
            array("namespaceUri" => "", "name" => "permission", "value" => "denied")
        ));

        $myVideoEntry->setExtensionElements(array($accessControlElement));

        $tokenArray = $yt->getFormUploadToken($myVideoEntry, "http://gdata.youtube.com/action/GetUploadToken");

        $nextUrl = urlencode("http://{$_SERVER['HTTP_HOST']}{$_SERVER['PHP_SELF']}?op=yt");

        print "<form action=\"{$tokenArray['url']}?nexturl={$nextUrl}\" method=\"POST\" enctype=\"multipart/form-data\">\n";
        print " <input name=\"file\" type=\"file\" />\n";
        print " <input name=\"token\" type=\"hidden\" value=\"{$tokenArray['token']}\" />\n";
        print " <input value=\"Upload Video File\" type=\"submit\" />\n";
        print "</form>\n";
    }
?>

Answer 1

我发现一篇优秀的文章对我有帮助:

http://jasonwritescode.blogspot.com/2013/09/youtube-browser-based-uploading-with.html

如果您使用本文来帮助您解决同样的问题，需要指出一些事情。 CURL 调用 http://gdata.youtube.com/action/GetUploadToken需要是HTTPS而不是HTTP，并且表单action="{{post_url}}?next={{next_url}}需要是action="{{post_url}}?nexturl={{next_url}}。