我想在 Umbraco Collection 上应用 where 条件。
代码:
var workList = CurrentPage.work.ToString().Split(new string[] { "," }, StringSplitOptions.RemoveEmptyEntries);
var workCollection = Umbraco.Content(workList);
@foreach (var item in workCollection.Where("productImage!=\"\"").Skip((i - 1) * iterationCount).Take(iterationCount))
最佳答案
如果你想坚持动态对象,你应该尝试:
var workList = CurrentPage.work.ToString().Split(new string[] { "," }, StringSplitOptions.RemoveEmptyEntries);
var workCollection = Umbraco.Content(workList);
@foreach (var item in workCollection.Where("productImage != null && productImage != string.Empty").Skip((i - 1) * iterationCount).Take(iterationCount)) { ... }
就我个人而言,我更喜欢处理强类型对象,因此另一种解决方案可能是:
var workList = CurrentPage.work.ToString().Split(new string[] { "," }, StringSplitOptions.RemoveEmptyEntries);
var workCollection = Umbraco.TypedContent(workList);
@foreach (IPublishedContent item in workCollection.Where(x => x.HasValue("productImage")).Skip((i - 1) * iterationCount).Take(iterationCount)) { ... }
欲了解更多信息,请查看:https://our.umbraco.org/documentation/reference/templating/mvc/querying .
您还可以检查名为Umbraco Core Property Value Converters的软件包:https://our.umbraco.org/projects/developer-tools/umbraco-core-property-value-converters/它会自动将一些数据类型值转换为易于访问的对象/列表等。媒体选择器值作为 IPublishedContent 模型返回,您可以直接从返回值访问其属性。
关于umbraco - 如何在 Umbraco Collection 上申请Where 条件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39367478/