引用这个问题:
Get count of items and their values in one column
如何在单个查询中获取记录计数的百分比,如下所示:
ItemId count Percent
------------------------------------
1 2 33.3
2 0 0
3 1 16.6
4 3 50.0
谢谢
最佳答案
COUNT(*) OVER()
给出总计数。
编辑但实际上您需要 SUM(COUNT(MyTbl.ItemID)) OVER()
来对该列中的值求和。
SELECT Items.ItemID,
[count] = COUNT(MyTbl.ItemID),
[Percent] = 100.0 * COUNT(MyTbl.ItemID) / SUM(COUNT(MyTbl.ItemID)) OVER()
FROM (VALUES (1,'N1'),
(2,'N2'),
(3,'N4'),
(4,'N5')) Items(ItemID, ItemName)
LEFT JOIN (VALUES(1),
(1),
(3),
(4),
(4),
(4)) MyTbl(ItemID)
ON ( MyTbl.ItemID = Items.ItemID )
GROUP BY Items.ItemID
ORDER BY Items.ItemID
关于sql - 获取单个查询中记录的计数百分比,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7340266/