sql - 解析字符串 SQL

Question

我在 MSSQL 中有一个非常长的字符串，我需要 I 值。

I代表发票， A代表金额， D代表日期

I=940;A=29.5;D=20090901|I=941;A=62.54;D=20090910|I=942;A=58.99;D=20091005|I=954;A=93.45;D=20091201|I=944;A=96.76;D=20091101|I=946;A=52.5;D=20091101|I=943;A=28.32;D=20091101|I=945;A=52.5;D=20091101|I=955;A=79.81;D=20091201|I=950;A=25.2;D=20091124|I=948;A=31.86;D=20091110|I=949;A=28.32;D=20091120|I=947;A=25.2;D=20091109|I=951;A=242.54;D=20091124|I=952;A=28.32;D=20091129|I=956;A=38.94;D=20091210|I=957;A=107.39;D=20091215|I=958;A=32.55;D=20091228|I=959;A=27.3;D=20091228|I=960;A=24.79;D=20091230|I=1117;A=28.32;D=20100131|I=1115;A=272.58;D=20100131|I=1116;A=159.6;D=20100209

这是最可怕的案例之一。

其中每一个都是具有相关值的发票号码，我将使用这些值链接到另一笔交易。如果有人能够解释在不制作应用程序的情况下实现此目的的最佳方式(如果可能)，我将非常感激

Answer 1

declare @s varchar(max) = 'I=940;A=29.5;D=20090901|I=941;A=62.54;D=20090910|I=942;A=58.99;D=20091005|I=954;A=93.45;D=20091201|I=944;A=96.76;D=20091101|I=946;A=52.5;D=20091101|I=943;A=28.32;D=20091101|I=945;A=52.5;D=20091101|I=955;A=79.81;D=20091201|I=950;A=25.2;D=20091124|I=948;A=31.86;D=20091110|I=949;A=28.32;D=20091120|I=947;A=25.2;D=20091109|I=951;A=242.54;D=20091124|I=952;A=28.32;D=20091129|I=956;A=38.94;D=20091210|I=957;A=107.39;D=20091215|I=958;A=32.55;D=20091228|I=959;A=27.3;D=20091228|I=960;A=24.79;D=20091230|I=1117;A=28.32;D=20100131|I=1115;A=272.58;D=20100131|I=1116;A=159.6;D=20100209'
declare @xml xml

select @xml = '<item><value>'+replace(replace(@s, ';','</value><value>'), '|','</value></item><item><value>')+'</value></item>'

select N.value('substring(value[1],3)', 'int') as Invoice,
       N.value('substring(value[2],3)', 'money') as Amount,
       N.value('substring(value[3],3)', 'date') as [Date]
from @xml.nodes('item') as T(N)

结果:

Invoice     Amount                Date
----------- --------------------- ----------
940         29,50                 2009-09-01
941         62,54                 2009-09-10
942         58,99                 2009-10-05
954         93,45                 2009-12-01
944         96,76                 2009-11-01
946         52,50                 2009-11-01
943         28,32                 2009-11-01
945         52,50                 2009-11-01
955         79,81                 2009-12-01
950         25,20                 2009-11-24
948         31,86                 2009-11-10
949         28,32                 2009-11-20
947         25,20                 2009-11-09
951         242,54                2009-11-24
952         28,32                 2009-11-29
956         38,94                 2009-12-10
957         107,39                2009-12-15
958         32,55                 2009-12-28
959         27,30                 2009-12-28
960         24,79                 2009-12-30
1117        28,32                 2010-01-31
1115        272,58                2010-01-31
1116        159,60                2010-02-09

对于 SQL Server 2005，您需要使用日期时间而不是日期

select N.value('substring(value[1],3)', 'int') as Invoice,
       N.value('substring(value[2],3)', 'money') as Amount,
       N.value('substring(value[3],3)', 'datetime') as [Date]
from @xml.nodes('item') as T(N)

要从表中读取数据，您需要这样做。

declare @s varchar(max) = 'I=940;A=29.5;D=20090901|I=941;A=62.54;D=20090910|I=942;A=58.99;D=20091005|I=954;A=93.45;D=20091201|I=944;A=96.76;D=20091101|I=946;A=52.5;D=20091101|I=943;A=28.32;D=20091101|I=945;A=52.5;D=20091101|I=955;A=79.81;D=20091201|I=950;A=25.2;D=20091124|I=948;A=31.86;D=20091110|I=949;A=28.32;D=20091120|I=947;A=25.2;D=20091109|I=951;A=242.54;D=20091124|I=952;A=28.32;D=20091129|I=956;A=38.94;D=20091210|I=957;A=107.39;D=20091215|I=958;A=32.55;D=20091228|I=959;A=27.3;D=20091228|I=960;A=24.79;D=20091230|I=1117;A=28.32;D=20100131|I=1115;A=272.58;D=20100131|I=1116;A=159.6;D=20100209'

declare @YourTable table(ID int, s varchar(max))
insert into @YourTable values
(1, @s),
(2, @s)

select Y.ID,
       T.N.value('substring(value[1],3)', 'int') as Invoice,
       T.N.value('substring(value[2],3)', 'money') as Amount,
       T.N.value('substring(value[3],3)', 'date') as [Date]
from @YourTable as Y
  cross apply (select cast('<item><value>'+replace(replace(Y.s, ';','</value><value>'), '|','</value></item><item><value>')+'</value></item>' as xml)) as X(XMLCol)
  cross apply X.XMLCol.nodes('item') as T(N)