我有一个String
数组
String student [] = {"BAT4M0ABBB4M0ABOH4M0CCHI4U0AENG4U0DMDM4U0B"}
我需要将其分割为每 7 个字符。 它应该看起来像这样:
String student {
"BAT4M0A",
"BBB4M0A",
"BOH4M0C",
"CHI4U0A",
"ENG4U0D",
"MDM4U0B"
}
这是我到目前为止的代码。
for (int i=0; i<= data.length; i++)
{
student= data[i].split(","); //data is a file of 1000 lines that is being read
if (student [2].equals(sN)) //student is a line in the each file that has been split into 11 parts
{
String timetable[]= student[9].split("(?<=\\G.......)");
System.out.println (timetable);
break;
}
最佳答案
你可以做
String[] array = student[0].split("(?<=\\G.{7})");
\G
是与最后一个匹配项匹配的元字符,因此 (?<=\\G.{7})
匹配空字符串后跟任意 7 个字符
关于java - 如何在java中将一个不带空格的字符串分割成多个单词?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21081553/