我正在尝试从以下 API 解析 JSON: https://opentdb.com/api.php?amount=1
但是当我尝试获取问题值时,出现以下错误:
Exception in thread "main" java.lang.NullPointerException
我使用这个代码:
public static void main(String[] args) throws IOException {
String question;
String sURL = "https://opentdb.com/api.php?amount=1"; //just a string
// Connect to the URL using java's native library
URL url = new URL(sURL);
URLConnection request = url.openConnection();
request.connect();
// Convert to a JSON object to print data
JsonParser jp = new JsonParser(); //from gson
JsonElement root = jp.parse(new InputStreamReader((InputStream) request.getContent())); //Convert the input stream to a json element
JsonObject rootobj = root.getAsJsonObject(); //May be an array, may be an object.
question = rootobj.get("question").getAsString(); //grab the question
}
希望有人能告诉我我做错了什么。
提前致谢!
最佳答案
当我查看您尝试解释的 JSON 时,我得到:
{
"response_code": 0,
"results":[
{
"category": "Entertainment: Board Games",
"type": "multiple",
"difficulty": "medium",
"question": "Who is the main character in the VHS tape included in the board game Nightmare?",
"correct_answer": "The Gatekeeper",
"incorrect_answers":["The Kryptkeeper","The Monster","The Nightmare"]
}
]
}
此 JSON 不包含根成员“question”
。这使得 rootobj.get("question")
返回 null
,因此对其调用 getAsString
会抛出 NullPointerException
.
因此,您必须遍历层次结构,而不是 rootobj.get("question")
:"results"
-> 第一个数组成员 -> “问题”
:
rootobj.getAsJsonArray("result").getAsJsonObject(0).get("question")
关于Java 从 URL NullPointerException 解析 JSON,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50800983/