我有一个图像,并且有一些值可以使其成为 Silverlight 中的透视图,但无法完全弄清楚我需要在数学上做什么才能实现它。最重要的是我有一个称为“视野”(FOV) 的角度。
这是正常的图片:
例如:
X = 30° X = 30° X = 30° FOV = 30° FOV = 60° FOV = 120° X = 60° X = 60° X = 60° FOV = 30° FOV = 60° FOV = 120°
如果能帮助我完成数学计算以在 Silverlight 中重现这些内容,我们将不胜感激。
最佳答案
我认为每个人都遇到的问题是需要随着透视变换而进行视口(viewport)移动。
试试这个:
private void ApplyProjection()
{
double fovY = FOV * Math.PI / 180 / 2.0;
double translationZ = -image1.ActualHeight / Math.Tan(fovY / 2.0);
double theta = YourAngleX * Math.PI / 180.0;
Matrix3D centerImageAtOrigin = TranslationTransform(
-image1.ActualWidth / 2.0,
-image1.ActualHeight / 2.0, 0);
Matrix3D invertYAxis = CreateScaleTransform(1.0, -1.0, 1.0);
Matrix3D rotateAboutY = RotateYTransform(theta);
Matrix3D translateAwayFromCamera = TranslationTransform(0, 0, translationZ);
Matrix3D perspective = PerspectiveTransformFovRH(fovY,
image1.ActualWidth / image1.ActualHeight, // aspect ratio
1.0, // near plane
1000.0); // far plane
Matrix3D viewport = ViewportTransform(image1.ActualWidth, image1.ActualHeight);
Matrix3D m = centerImageAtOrigin * invertYAxis;
m = m * rotateAboutY;
m = m * translateAwayFromCamera;
m = m * perspective;
m = m * viewport;
Matrix3DProjection m3dProjection = new Matrix3DProjection();
m3dProjection.ProjectionMatrix = m;
image1.Projection = m3dProjection;
}
private Matrix3D TranslationTransform(double tx, double ty, double tz)
{
Matrix3D m = new Matrix3D();
m.M11 = 1.0; m.M12 = 0.0; m.M13 = 0.0; m.M14 = 0.0;
m.M21 = 0.0; m.M22 = 1.0; m.M23 = 0.0; m.M24 = 0.0;
m.M31 = 0.0; m.M32 = 0.0; m.M33 = 1.0; m.M34 = 0.0;
m.OffsetX = tx; m.OffsetY = ty; m.OffsetZ = tz; m.M44 = 1.0;
return m;
}
private Matrix3D CreateScaleTransform(double sx, double sy, double sz)
{
Matrix3D m = new Matrix3D();
m.M11 = sx; m.M12 = 0.0; m.M13 = 0.0; m.M14 = 0.0;
m.M21 = 0.0; m.M22 = sy; m.M23 = 0.0; m.M24 = 0.0;
m.M31 = 0.0; m.M32 = 0.0; m.M33 = sz; m.M34 = 0.0;
m.OffsetX = 0.0; m.OffsetY = 0.0; m.OffsetZ = 0.0; m.M44 = 1.0;
return m;
}
private Matrix3D RotateYTransform(double theta)
{
double sin = Math.Sin(theta);
double cos = Math.Cos(theta);
Matrix3D m = new Matrix3D();
m.M11 = cos; m.M12 = 0.0; m.M13 = -sin; m.M14 = 0.0;
m.M21 = 0.0; m.M22 = 1.0; m.M23 = 0.0; m.M24 = 0.0;
m.M31 = sin; m.M32 = 0.0; m.M33 = cos; m.M34 = 0.0;
m.OffsetX = 0.0; m.OffsetY = 0.0; m.OffsetZ = 0.0; m.M44 = 1.0;
return m;
}
private Matrix3D RotateZTransform(double theta)
{
double cos = Math.Cos(theta);
double sin = Math.Sin(theta);
Matrix3D m = new Matrix3D();
m.M11 = cos; m.M12 = sin; m.M13 = 0.0; m.M14 = 0.0;
m.M21 = -sin; m.M22 = cos; m.M23 = 0.0; m.M24 = 0.0;
m.M31 = 0.0; m.M32 = 0.0; m.M33 = 1.0; m.M34 = 0.0;
m.OffsetX = 0.0; m.OffsetY = 0.0; m.OffsetZ = 0.0; m.M44 = 1.0;
return m;
}
private Matrix3D PerspectiveTransformFovRH(double fieldOfViewY, double aspectRatio, double zNearPlane, double zFarPlane)
{
double height = 1.0 / Math.Tan(fieldOfViewY / 2.0);
double width = height / aspectRatio;
double d = zNearPlane - zFarPlane;
Matrix3D m = new Matrix3D();
m.M11 = width; m.M12 = 0; m.M13 = 0; m.M14 = 0;
m.M21 = 0; m.M22 = height; m.M23 = 0; m.M24 = 0;
m.M31 = 0; m.M32 = 0; m.M33 = zFarPlane / d; m.M34 = -1;
m.OffsetX = 0; m.OffsetY = 0; m.OffsetZ = zNearPlane * zFarPlane / d; m.M44 = 0;
return m;
}
private Matrix3D ViewportTransform(double width, double height)
{
Matrix3D m = new Matrix3D();
m.M11 = width / 2.0; m.M12 = 0.0; m.M13 = 0.0; m.M14 = 0.0;
m.M21 = 0.0; m.M22 = -height / 2.0; m.M23 = 0.0; m.M24 = 0.0;
m.M31 = 0.0; m.M32 = 0.0; m.M33 = 1.0; m.M34 = 0.0;
m.OffsetX = width / 2.0; m.OffsetY = height / 2.0; m.OffsetZ = 0.0; m.M44 = 1.0;
return m;
}
这将创建适当的视角转换并与 PowerPoint 生成的内容相匹配。
此代码改编自MSDN .
关于.net - 如何在Matrix3D中设置这种透视变换?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/3250744/