架构如下:
CREATE TABLE [Structure](
[StructureId] [uniqueidentifier] NOT NULL,
[SequenceNumber] [int] NOT NULL, -- order for siblings, unique per parent
[ParentStructureId] [uniqueidentifier] NULL,
CONSTRAINT [Structure_PK] PRIMARY KEY CLUSTERED
(
[StructureId] ASC
)
) ON [PRIMARY]
ALTER TABLE [Structure] WITH CHECK ADD CONSTRAINT [Structure_FK1]
FOREIGN KEY([ParentStructureId])
REFERENCES [Structure] ([StructureId])
目前,我可以使用以下 CTE 获取所有逻辑数据,但我想以深度优先的方式直接打印它。
WITH SCTE (StructureId, Level, Seq, ParentId)
AS
(
SELECT StructureId, 0, SequenceNumber, [ParentStructureId]
FROM Structure
WHERE [ParentStructureId] IS NULL
AND StructureId = 'F6C5F016-1270-47C1-972F-349C32DFC92A'
UNION ALL
SELECT Structure.StructureId, Level + 1, SequenceNumber, ParentStructureId
FROM Structure
INNER JOIN SCTE ON SCTE.StructureId = Structure.ParentStructureId
)
SELECT * FROM SCTE
ORDER BY Level, ParentId, Seq
输出如下(此处截断):
StructureId Level Seq ParentId
F6C5F016-1270-47C1-972F-349C32DFC92A 0 0 NULL
D2E34429-401A-4A49-9E18-E81CCA0FB417 1 0 F6C5F016-1270-47C1-972F-349C32DFC92A
0CC5E16C-9194-40CA-9F72-1CED2972D7CA 1 1 F6C5F016-1270-47C1-972F-349C32DFC92A
1ECD1D30-EB85-42B0-969F-75794343E3B4 1 2 F6C5F016-1270-47C1-972F-349C32DFC92A
EEC3A981-B790-4600-8CD1-F15972CD9230 2 0 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
4406F639-2F58-4918-A9EF-A4B0F379BEA0 2 1 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
FCAF7870-C606-4AA6-85EE-57B90B1B0CC3 2 2 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
855DF5FB-1593-4E5B-8EF9-3770B45F89D6 2 3 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
3D16DF32-C04F-49B4-B0D9-5BDC9104F810 2 4 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
A1084D00-0198-47D9-87E0-BB8234233F14 2 5 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
CE443C0D-376F-46EC-9914-32C6B7200DB1 2 6 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
0DEA587D-4FCF-414C-AD71-FB00829F8082 2 7 0CC5E16C-9194-40CA-9F72-1CED2972D7CA
CC9FC8D3-254A-486B-8DC4-07E57627476C 2 0 1ECD1D30-EB85-42B0-969F-75794343E3B4
215565CC-501F-4850-B8AE-5466DA5E6854 2 1 1ECD1D30-EB85-42B0-969F-75794343E3B4
D4E6C8E5-5ADD-4AD1-B59B-1A672F66888A 2 2 1ECD1D30-EB85-42B0-969F-75794343E3B4
796C65BF-4714-4DBF-A97A-2150DBE3098C 2 3 1ECD1D30-EB85-42B0-969F-75794343E3B4
B39DEB9C-BE42-43B4-9C38-968399D7D1E2 2 4 1ECD1D30-EB85-42B0-969F-75794343E3B4
6C2F70C6-1DA0-4E1A-BBC1-D7FCAFE6AFEE 2 0 D2E34429-401A-4A49-9E18-E81CCA0FB417
75D7B43B-C971-46B4-BC42-58C3605ADD79 2 1 D2E34429-401A-4A49-9E18-E81CCA0FB417
0B5AAAA0-A69F-431E-86BA-148444D7B1E6 2 2 D2E34429-401A-4A49-9E18-E81CCA0FB417
CB3CF66B-D83A-45E2-953A-6F0CEE094F5B 2 3 D2E34429-401A-4A49-9E18-E81CCA0FB417
1D5F69C3-F036-4667-BD75-A0DC1506DB6D 2 4 D2E34429-401A-4A49-9E18-E81CCA0FB417
71B894F7-B9FC-44DE-AEDB-E6FA026A6082 2 5 D2E34429-401A-4A49-9E18-E81CCA0FB417
F1DFA1E1-013B-449C-9D9D-14C64E75D418 2 6 D2E34429-401A-4A49-9E18-E81CCA0FB417
正如您所看到的,结果是“广度优先”,这使得像现在这样打印树有点不可能。
有没有办法(可能有一个简单的方法,但我的 SQL 技能非常差)以“树打印友好”格式获取结果列表?
我知道我可以将结果转储到程序中并对输出进行编码,但作为练习,我更喜欢在 SQL 本身中执行此操作。
谢谢
最佳答案
评论后编辑。您可以添加节点的路径,并对其进行排序:
declare @t table (id int, parent int)
insert @t (id, parent) values (1, null), (2,1), (3,2), (4,3), (5,null), (6,5)
; with cte as (
select id, parent
, cast(RIGHT(REPLICATE('0',12) +
CONVERT(varchar(12),id),12) as varchar(max)) Path
from @t
where parent is null
union all
select child.id, child.parent
, parent.Path + RIGHT(REPLICATE('0',12) +
CONVERT(varchar(12),child.id),12) as Path
from @t child
join cte parent
on parent.id = child.parent
)
select *
from cte
order by
Path
这将首先打印根,然后按顺序打印叶。如果您的 ID 可能大于 12 位数字,请增加 char(x)
转换中的数字。
关于sql-server - 使用 SQL CTE 打印树,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4032192/