spring - 如何从 wsdl 文件内的属性文件读取？

Question

我在 src/wsdl 下有 wsdl 文件，我想知道是否可以从此 wsdl 文件内的属性文件读取值，如下所示:

<?xml version="1.0" encoding="UTF-8"?><!-- Published by JAX-WS RI at http://jax-ws.dev.java.net. RI's version is JAX-WS RI 2.1.3-b02-. --><!-- Generated by JAX-WS RI at http://jax-ws.dev.java.net. RI's version is JAX-WS RI 2.1.3-b02-. --><definitions xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:tns="http://AXLInterface.jaxws.AllInOne.org/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://schemas.xmlsoap.org/wsdl/" targetNamespace="http://AXLInterface.jaxws.AllInOne.org/" name="AXLInterfaceService">
<types>
<xsd:schema>
<xsd:import namespace="http://AXLInterface.jaxws.AllInOne.org/" schemaLocation="${wsdl.url}/AXLInterface?xsd=1"></xsd:import>
</xsd:schema>

</definitions>

我在 applicationContext 中定义了 PropertyPlaceholderConfigurer ，如下所示:

<bean id="propertyConfigurer"
        class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <property name="locations">
            <list>
                <value>classpath:messages/application.properties</value>
                <value>file:${APP_HOME}/Common/Conf/app.properties
                </value>
            </list>
        </property>

        <property name="ignoreResourceNotFound" value="true" />
        <property name="searchSystemEnvironment" value="true" />
        <property name="systemPropertiesModeName" value="SYSTEM_PROPERTIES_MODE_OVERRIDE" />
    </bean>

当我尝试编译应用程序时，我在 wsdl 文件中遇到错误:

[ERROR] Unable to parse "${wsdl.url}/AXLInterface?xsd=1" : Illegal character in path at index 1: ${wsdl.url}/AXLInterface?xsd=1

[ERROR] java.net.URISyntaxException: Illegal character in path at index 1: ${wsdl.url}/AXLInterface?xsd=1

请告知如何实现这一点，谢谢。

Answer 1

只需将 WSDL 文件定义为资源，Maven 就会对其进行过滤。但属性值应该位于 Maven 配置文件中，而不是属性文件中。

<resource>
    <directory>src/wsdl</directory>
    <filtering>true</filtering>
</resource>