我尝试使用下面的正则表达式从 requestURI 中提取电子邮件地址，这是基于 RFC-2822 的电子邮件正则表达式，它与验证配合良好
private final transient String EMAIL_REGEX =
"^([^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]"
+ "+|\\x22([^\\x0d\\x22\\x5c\\x80-\\xff]|\\x5c[\\x00-\\x7f])*\\x22)"
+ "(\\x2e([^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]+"
+ "|\\x22([^\\x0d\\x22\\x5c\\x80-\\xff]|\\x5c[\\x00-\\x7f])*\\x22))"
+ "*\\x40([^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]+"
+ "|\\x5b([^\\x0d\\x5b-\\x5d\\x80-\\xff]|\\x5c[\\x00-\\x7f])*\\x5d)"
+ "(\\x2e([^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]"
+ "+|\\x5b([^\\x0d\\x5b-\\x5d\\x80-\\xff]|\\x5c[\\x00-\\x7f])*\\x5d))*$";
我正在尝试重用相同的正则表达式来匹配并从 URI /something/users/myemail@email.com/somethingelse 中提取电子邮件地址，并使用 Matcher.group( 0) 我得到输出 /something/users/myemail@email.com ，因为我的预期输出只是 URI 中的电子邮件地址。
最佳答案
我提出了这个正则表达式更新:
private static String EMAIL_REGEX =
"([^/\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]"
+ "+|\\x22([^\\x0d\\x22\\x5c\\x80-\\xff]|\\x5c[\\x00-\\x7f])*\\x22)"
+ "(\\x2e([^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]+"
+ "|\\x22([^\\x0d\\x22\\x5c\\x80-\\xff]|\\x5c[\\x00-\\x7f])*\\x22))"
+ "*\\x40([^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]+"
+ "|\\x5b([^\\x0d\\x5b-\\x5d\\x80-\\xff]|\\x5c[\\x00-\\x7f])*\\x5d)"
+ "(\\x2e([^/\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]"
+ "+|\\x5b([^\\x0d\\x5b-\\x5d\\x80-\\xff]|\\x5c[\\x00-\\x7f])*\\x5d))*";
请注意开头和倒数第二行的[^/\\x00。
请参阅online demo
String s = "/something/users/myemail@email.com/somethingelse";
Matcher m = Pattern.compile(EMAIL_REGEX).matcher(s);
while (m.find())
{
System.out.println(m.group());
} // => myemail@email.com
关于Java - 使用正则表达式从 requestURI 中提取电子邮件地址，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33854488/