grails - 在 Groovy/Grails 中设置 new URL(...).text 的超时

Question

我使用以下 Groovy 代码片段来获取 Grails 应用程序中 HTML 页面的纯文本表示形式:

String str = new URL("http://www.example.com/some/path")?.text?.decodeHTML()

现在我想更改代码，以便请求在 5 秒后超时(导致 str == null)。实现这一目标的最简单且最 Groovy 的方法是什么？

Answer 1

我检查了groovy 2.1.8的源代码，以下代码可用:

'http://www.google.com'.toURL().getText([connectTimeout: 2000, readTimeout: 3000])

<小时/>

处理配置映射的逻辑位于方法org.codehaus.groovy.runtime.ResourceGroovyMethods#configuredInputStream

private static InputStream configuredInputStream(Map parameters, URL url) throws IOException {
    final URLConnection connection = url.openConnection();
    if (parameters != null) {
        if (parameters.containsKey("connectTimeout")) {
            connection.setConnectTimeout(DefaultGroovyMethods.asType(parameters.get("connectTimeout"), Integer.class));
        }
        if (parameters.containsKey("readTimeout")) {
            connection.setReadTimeout(DefaultGroovyMethods.asType(parameters.get("readTimeout"), Integer.class));
        }
        if (parameters.containsKey("useCaches")) {
            connection.setUseCaches(DefaultGroovyMethods.asType(parameters.get("useCaches"), Boolean.class));
        }
        if (parameters.containsKey("allowUserInteraction")) {
            connection.setAllowUserInteraction(DefaultGroovyMethods.asType(parameters.get("allowUserInteraction"), Boolean.class));
        }
        if (parameters.containsKey("requestProperties")) {
            @SuppressWarnings("unchecked")
            Map<String, String> properties = (Map<String, String>) parameters.get("requestProperties");
            for (Map.Entry<String, String> entry : properties.entrySet()) {
                connection.setRequestProperty(entry.getKey(), entry.getValue());
            }
        }

    }
    return connection.getInputStream();
}